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andrey2020 [161]
3 years ago
14

HELP I WILL GIVE BRAINLIEST I PROMISE

Mathematics
2 answers:
Irina-Kira [14]3 years ago
8 0

Answer:

m ≤ $14.25

Step-by-step explanation:

Aleks04 [339]3 years ago
8 0

Answer:

m ≤ $80.75

Step-by-step explanation:

hope it helps

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What is the period of the sinusoidal function? Enter your answer in the box.
muminat

Answer:

ANSWER:

The period of the sinusoidal function is 2π.

Step-by-step explanation:

EXPLANATION:

The sinusoidal function is a periodic function.It goes one unit up and one unit down with an amplitude of one and it repeats itself after this time interval.So,the period of the sine function is 2π

A sine or sinusoidal loop is a perpetual swing. It is called after the role sine. It happens frequently in tentative and practiced math, science, physics, engineering,  signal processing, and other disciplines. Its utmost fundamental pattern as a role of time (t).

3 0
3 years ago
Problem<br> 3 erasers cost $4.41<br> Which equation would help determine the cost of 4 erasers?
Phantasy [73]

Answer:

4.41/ 3 = 1.47 each

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
4r^3-3r^2-4r+3 <br> four terms <br> use grouping
matrenka [14]
It’s (4r-3)(r+1)(r-1)
5 0
3 years ago
Find a point slope form for the line with slope 1/5 and passing through the point (-3,-9)
alisha [4.7K]

Answer:

y+9=1/5(x+3)

Step-by-step explanation:

Point slope formula: y-y1=m(x-x1)

slope=m

m=1/5

-3=x1 -9=y1

y-(-9) =1/5(x-(-3))

simplify...

y+9=1/5(x+3)

hope this helps!! :)

5 0
3 years ago
P is the point on the line 2x+y-10=0 such that the length of OP, the line segment from the origin O to P, is a minimum. Find the
nirvana33 [79]
The minimum distance is the perpendicular distance. So establish the distance from the origin to the line using the distance formula.
The distance here is: <span><span>d2</span>=(x−0<span>)^2</span>+(y−0<span>)^2
</span>                                      =<span>x^2</span>+<span>y^2
</span></span>
To minimize this function d^2 subject to the constraint, <span>2x+y−10=0
</span>If we substitute, the y-values the distance function can take will be related to the x-values by the line:<span>y=10−2x 
</span>You can substitute this in for y in the distance function and take the derivative:
<span>d=sqrt [<span><span><span>x2</span>+(10−2x<span>)^2]
</span></span></span></span>
d′=1/2 (5x2−40x+100)^(−1/2)   (10x−40)<span>
</span>Setting the derivative to zero to find optimal x,
<span><span>d′</span>=0→10x−40=0→x=4
</span>
This will be the x-value on the line such that the distance between the origin and line will be EITHER a maximum or minimum (technically, it should be checked afterward).
For x = 4, the corresponding y-value is found from the equation of the line (since we need the corresponding y-value on the line for this x-value).
 
Then y = 10 - 2(4) = 2.
 So the point, P, is (4,2).
8 0
3 years ago
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