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dezoksy [38]
2 years ago
14

PLEASE HELP!!!!!!!!!!!!

Mathematics
2 answers:
andrew11 [14]2 years ago
7 0
The answer is b
hope that helps:)
daser333 [38]2 years ago
6 0

Answer:

b

Step-by-step explanation:

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A quarter coin is tossed two times. What is the probability that the coin will land heads up both times?
Brut [27]

Answer:

1 in 4 chance

Step-by-step explanation:

because if it is a 50% chance to get heads on one toss, then for two tosses you have to multiply 1/2 * 1/2 and that equals 1/4

8 0
3 years ago
Rafeal wants to know if there is a single transformation that will move trapezoid JKLM onto trapezoid PQRS Below
aliina [53]

A. A 90° counterclockwise rotation of trapezoid JKLM about the origin will move angle L onto angle R.

Step-by-step explanation:

Since both the trapezoids, trapezoid JKLM and PQRS are congruent, we can do any transformation, may be rotation, reflection and translation.

A 90° counterclockwise rotation of trapezoid JKLM about the origin will move angle L onto angle R is the true statement others are incorrect statements.

When the Preimage is rotated 90° counterclockwise rotation, then its coordinates (x,y) changed into (-y,x)  

8 0
3 years ago
What’s the answer to the question mark
melamori03 [73]

The missing number is 20

<h3>How to determine the number</h3>

We can see that the values at the top must be made equal to that at the bottom

For the top, we have

30 + 11 = 41

For the bottom, we should have:

21 + x = 41

Now, let's solve for 'x' to determine the missing figure;

21 + x = 41

collect like terms

x = 41 - 21

x = 20

Thus, the missing number is 20

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6 0
2 years ago
Find all real solutions to the equation (x² − 6x +3)(2x² − 4x − 7) = 0.
Jet001 [13]

Answer:

x = 3 + √6 ; x = 3 - √6 ; x = \frac{2+3\sqrt{2}}{2} ;  x = \frac{2-(3)\sqrt{2}}{2}

Step-by-step explanation:

Relation given in the question:

(x² − 6x +3)(2x² − 4x − 7) = 0

Now,

for the above relation to be true the  following condition must be followed:

Either  (x² − 6x +3) = 0 ............(1)

or

(2x² − 4x − 7) = 0 ..........(2)

now considering the equation (1)

(x² − 6x +3) = 0

the roots can be found out as:

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

for the equation ax² + bx + c = 0

thus,

the roots are

x = \frac{-(-6)\pm\sqrt{(-6)^2-4\times1\times(3)}}{2\times(1)}

or

x = \frac{6\pm\sqrt{36-12}}{2}

or

x = \frac{6+\sqrt{24}}{2} and, x = x = \frac{6-\sqrt{24}}{2}

or

x = \frac{6+2\sqrt{6}}{2} and, x = x = \frac{6-2\sqrt{6}}{2}

or

x = 3 + √6 and x = 3 - √6

similarly for (2x² − 4x − 7) = 0.

we have

the roots are

x = \frac{-(-4)\pm\sqrt{(-4)^2-4\times2\times(-7)}}{2\times(2)}

or

x = \frac{4\pm\sqrt{16+56}}{4}

or

x = \frac{4+\sqrt{72}}{4} and, x = x = \frac{4-\sqrt{72}}{4}

or

x = \frac{4+\sqrt{2^2\times3^2\times2}}{2} and, x = x = \frac{4-\sqrt{2^2\times3^2\times2}}{4}

or

x = \frac{4+(2\times3)\sqrt{2}}{2} and, x = x = \frac{4-(2\times3)\sqrt{2}}{4}

or

x = \frac{2+3\sqrt{2}}{2} and, x = \frac{2-(3)\sqrt{2}}{2}

Hence, the possible roots are

x = 3 + √6 ; x = 3 - √6 ; x = \frac{2+3\sqrt{2}}{2} ; x = \frac{2-(3)\sqrt{2}}{2}

7 0
3 years ago
Use properties to find the sum or product<br>8 x 51
Lostsunrise [7]

8(51)

=8(50+1)

=8*50+8*1

=8*5*10+8*1

=400+8

=408

5 0
3 years ago
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