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3 years ago

I need help with #18 c-i

Mathematics

1 answer:

Lostsunrise [7]3 years ago

3 0

C - one is -4 due to that when y=0 the x coordinate shows -4, the other is when 4-x^2=0, and the square root of 4 is 2

d - x intercepts

e - it's 4 due to that 4 is shown where x=0 on the graph

f - y intercept

g - Since x>0, we do 4-x^2. x=1, and 1^2=1, so 4-1=3. 1 is x and 3 is f(x), or y, so the coordinates are (1,3)

h - Since it's <0, -1+4=3, and since 3 is the output the coordinates are (-1,3)

i - Since -3 <0, we do -3+4=1

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Solve using the quadratic formula 3x^2+11x+5=0

storchak [24]

Answer:

$3x^2 + 11x + 5 = 0 : x = \frac{-11 + \sqrt{61} }{6} , x = \frac{-11 - \sqrt{61} }{6}$

Decimal:

$(x = -0.53162..., x = -3.13504...)$

Step-by-step explanation:

$3x^2+11x+5=0$

Solve with the quadratic formula:

For a quadratic equation of the form $ax^2+bx+c=0$ the solutions are:

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

For $a=3,\:b=11,\:c=5:\quad x_{1,\:2}=\frac{-11\pm \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3}$

$x=\frac{-11 + \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3} : \frac{-11 + \sqrt{61} }{6}$

$x=\frac{-11 - \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3} : \frac{-11 - \sqrt{61} }{6}$

The solutions to the quadratic equation are:

$x=\frac{-11+\sqrt{61}}{6},\:x=\frac{-11-\sqrt{61}}{6}$

Hope I helped. If so, may I get brainliest and a thanks?

Thank you, have a good day! =)

8 0

3 years ago

A store advertised 15% off an idem that regularly sells for 300

Alex_Xolod [135]

The answer is 45.
15% = 0.15, since you move the decimal 2 places
0.15 x 300 = 45.

3 0

3 years ago

Which statement is true about the function f(x)= StartRoot negative x EndRoot?

UNO [17]

Answer:

The domain of the graph is all real numbers less than or equal to 0

Step-by-step explanation:

we have the function

$f(x)=\sqrt{-x}$

we know that

The radicand must be positive

$-x \geq 0$

Solve for x

Multiply by -1 both sides

$x\leq 0$

The domain is the interval ------> (-∞,0]

All real numbers less than or equal to zero

The range of the function is the interval -----> [0,∞)

$f(x)\geq 0$

see the attached figure to better understand the problem

All real numbers greater than or equal to zero

<em><u>Verify each statement</u></em>

case 1) The domain of the graph is all real numbers

The statement is false

Because, the domain is all real numbers less than or equal to zero

case 2) The range of the graph is all real numbers

The statement is false

Because, the range is all real numbers greater than or equal to zero

case 3) The domain of the graph is all real numbers less than or equal to 0

The statement is true

case 4) The range of the graph is all real numbers less than or equal to 0

The statement is false

Because, the range is all real numbers greater than or equal to zero

4 0

3 years ago

Read 2 more answers

NEED HELP WITH

Fed [463]

Let the average profit or loss in year 2006 be x millions,

The average profit for the 8-year period, is the total sum of the profits (or losses) of each year, divided by 8:

so we have:

$\displaystyle{ \frac{3.40+2.10+x+0.60+2.10+0.20+1.30+0.75}{8}=1$

$\displaystyle{\frac{10.45+x}{8}=1$

$10.45+x=8$

x=8-10.45=-2.45

Answer: the loss in 2006, was 2.45 million dollars

3 0

3 years ago

What equation in slope-intercept form represents the line that passes through

gregori [183]

Answer:

So, equation in slope-intercept form that represents the line that passes through the points (1,3) and (2,5) is y=2x+1

Step-by-step explanation:

We need to write equation in slope intercept form that represents the line that passes through the points (1,3) and (2,5)

The standard equation of slope-intercept form is: y= mx+b

where m is the slope of the lines and b is the y-intercept.

To make the equation we need to find slope (m) and y-intercept (b)

Find Slope