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3 years ago

Which of the following is the scientific notation for the number 0.00001526?

Mathematics

1 answer:

Viefleur [7K]3 years ago

7 0

Answer:

the answer is d

Step-by-step explanation:

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How many seconds will light leaving Los Angeles take to reach the following locations (a) San Francisco (about 500km), (b) Londo

kondor19780726 [428]

Answer:

a) It takes 0.0017s for the light to reach San Francisco.

b) It takes 0.033s for the light to reach London.

c) It takes 1.334s for the light to reach Mars.

d) It takes 149.7s for the light to reach Venus.

Step-by-step explanation:

Here we can solve this problem by using this following formula:

$s = \frac{d}{t}$

In which s is the speed(in km/s), d is the distance(in km) and t is the time(in s).

The light speed is 299 792 458 m / s = 299,792.458 km/s, so $s = 299,792.458$

(a) San Francisco (about 500km)

Find t when $d = 500$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{500}{t}$

$299,792.458t = 500$

$t = \frac{500}{299,792.458}$

$t = 0.0017s$

It takes 0.0017s for the light to reach San Francisco.

b) London(about 10,000km)

Find t when $d = 10,000$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{10,000}{t}$

$299,792.458t = 10,000$

$t = \frac{10,000}{299,792.458}$

$t = 0.033s$

It takes 0.033s for the light to reach London.

(c) the Moon (400,000km)

Find t when $d = 400,000$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{400,000}{t}$

$299,792.458t = 400,000$

$t = \frac{400,000}{299,792.458}$

$t = 1.334s$

It takes 1.334s for the light to reach Mars.

(d) Venus (0.3 A.U. from Earth at its closest approach).

Each A.U. has 149,59,7871 km.

So 0.3 A.U. = 0.3*(149,597,871) = 44,879,361.3. This means that $d = 44,879,361.3$ . So:

$s = \frac{d}{t}$

$299,792.458 = \frac{44,879,361.3}{t}$

$299,792.458t = 44,879,361.3$

$t = \frac{44,879,361.3}{299,792.458}$

$t = 149.7s$

It takes 149.7s for the light to reach Venus.

3 0

3 years ago

What is the constant rate of y=3/4x

Sonja [21]

Answer:

that would be 3/4

Step-by-step explanation:

7 0

3 years ago

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Drag the correct symbol into the box to compare the expressions.

julsineya [31]

There you go! Hope this helped!✌️

4 0

3 years ago

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What methods have you learned to calculate the determinant of a matrix? Compare the numerical efficiency of both the methods. Li

Arada [10]

Honestly i don’t know but you can try to figure it out

4 0

4 years ago

Katherine is considering two new cell phone plans. She doesn't want to spend more for minutes she won't use. One plan allows up

mojhsa [17]

Answer:

The first plan of $49 will be best plan for her.

Step-by-step explanation:

Katherine used 1479 minutes call in the last 6 months.

So, the average monthly call that Katherine made is $\frac{1479}{6} =246.5$ minutes.

Now, there are two plans for mobile recharge.

One is 250 minutes call time for $49 and the other is 350 minutes call time for $65.

Since 246.5 < 250 and Katherine does not want to spend more for minutes she won't use, then the first plan of $49 will be the best plan for her. (Answer)

8 0

3 years ago