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2 years ago

Write the equation if this line below

Mathematics

1 answer:

tatuchka [14]2 years ago

3 0

Answer:

y=3/4x+2

Step-by-step explanation:

2 is the y intercept.

Go up 3 right 4 to reach a even point.

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What is (-4,-7) and (-6,9) in slope intercept form

quester [9]

Answer:

y = - 8x - 39

8 0

3 years ago

Using the polynomials Q = 3x 2 + 5x - 2, R = 2 - x 2, and S = 2x + 5, perform the indicated operation: Q - [R + S]

sleet_krkn [62]

(3x^2+5x-2)- ((2-x^2+2x+5))
(3x^2+5x-2)- ((7-x^2+2x))
Since no more can be added or broken down
3x^2+5x-2 - 7-x^2+2x
2x^2+7x-9

5 0

3 years ago

Read 2 more answers

Without a calculator how would you solve this?

mina [271]

Answer:

the largest number that is less than (2+√3)^6 is 2701

Step-by-step explanation:

$\bigstar \ (2+\sqrt{3})^6= \\\\C{}^{0}_{6}2^{6}+C{}^{1}_{6}2^{5}\sqrt{3}^1+C{}^{2}_{6}2^{4}\sqrt{3}^2+C{}^{3}_{6}2^{3}\sqrt{3}^3+C{}^{4}_{6}2^{2}\sqrt{3}^4+C{}^{5}_{6}2^{1}\sqrt{3}^5+C{}^{6}_{6}\sqrt{3}^6$

$=64+192\sqrt{3}+720 +480\sqrt{3} +540+108\sqrt{3} +27\\=1351+780\sqrt{3}$

$\bigstar\ (2-\sqrt{3} )^6 =\\\\1351-780\sqrt{3}$

$\bigstar\ \bigstar\ (2+\sqrt{3} )^6+(2-\sqrt{3} )^6 =\\\\1351+780\sqrt{3}+1351-780\sqrt{3}$

$\Longrightarrow(2+\sqrt{3} )^6+(2-\sqrt{3} )^6 =2702$

$\Longrightarrow(2+\sqrt{3} )^6 =2702-(2-\sqrt{3} )^6$

$0 < \left( 2-\sqrt{3} \right) < 1 \Longrightarrow 0 < \left( 2-\sqrt{3} \right)^{6} < 1 \Longrightarrow-1 < \left( 2-\sqrt{3} \right)^{6} < 0$

$\Longrightarrow2702-1 < 2702-\left( 2-\sqrt{3} \right)^{6} < 2702+0$

$\Longrightarrow 2701 < \left( 2+\sqrt{3} \right)^{6} < 2702$

8 0

2 years ago

The time period, T, of a simple pendulum is directly proportional to the square root of the length, d, of the pendulum.

bearhunter [10]

Answer: T= 3.54

Step-by-step explanation:

Step 1

Given that

The time period, T, s doirectly proportional to the square root of the length, d, of the pendulum, we have that

T ∝ $\sqrt{d}$

Introducing the constant of proportionality, we have that

T= K $\sqrt{d}$ .

Step 2

When d=6, T=5, K =?

T= K $\sqrt{d}$ .

5 = k $\sqrt{6}$

5= k x 2.44949

k =5/2.44949

k =2.041

Therefore, when d = 3 , T= ?

T= K $\sqrt{d}$

T= 2.041 x $\sqrt{3}$

T= 3.53511≈ 3.54

4 0

3 years ago

Six hundred eight thousandths

Leya [2.2K]

6,008 is six hundred and eight thousand.

5 0

3 years ago

Read 2 more answers

Write the equation if this line below​

Write the equation if this line below