For this, I got the equation (X+3)^2-2 or X^2+6X+7. I used this method:
First I set up an equation (X+H)^2-K, where (K, H) is the vertex. All we have to do is find where the graph reaches its minimum value (because it opens upwards), then find the x-coordinate that lies there, which is (-2,3). Substituting these value in for H and K, we get the equation <span>(X+3)^2-2 or simplified X^2+6X+7.
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Answer:
Distance around the pool = 162.8 feet
Area of the pool = 957 square feet
Step-by-step explanation:
Distance around the swimming pool = Perimeter of the pool
Perimeter of the pool which is a composite figure will be,
= Circumference of the semicircle + Sum of three sides of the pool
= πr + 2×(length of the pool) + width of the pool
= 3.14×(10) + 2×40 + 20
= 62.8 + 80 + 20
= 162.8 ft
Area of the pool = Area of the semicircle + Area of the rectangular pool
= 
= 
= 157 + 800
= 957 square feet
Answer:
y = -
x + 3
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (0, 3) and (x₂, y₂ ) = (4, 0) ← 2points on the line
m =
= - 
Note the line crosses the y- axis at (0, 3 ) ⇒ c = 3
y = -
x + 3 ← equation of line