<span>use De Moivre's Theorem:
⁵√[243(cos 260° + i sin 260°)] = [243(cos 260° + i sin 260°)]^(1/5)
= 243^(1/5) (cos (260 / 5)° + i sin (260 / 5)°)
= 3 (cos 52° + i sin 52°)
z1 = 3 (cos 52° + i sin 52°) ←← so that's the first root
there are 5 roots so the angle between each root is 360/5 = 72°
then the other four roots are:
z2 = 3 (cos (52 + 72)° + i sin (52+ 72)°) = 3 (cos 124° + i sin 124°)
z3 = 3 (cos (124 + 72)° + i sin (124 + 72)°) = 3 (cos 196° + i sin 196°)
z4 = 3 (cos (196 + 72)² + i sin (196 + 72)°) = 3 (cos 268° + i sin 268°)
z5 = 3 (cos (268 + 72)° + i sin (268 + 72)°) = 3 (cos 340° + i sin 340°) </span>
Answer:
the answer is
6.41
12.78
17.226
Step-by-step explanation:
I think it may be 5+3 and carry the one up top to get the sum of 56.
A. The area of a square is given as:
<span>A = s^2 </span>
Where s is a measure of a side of a square. s = (2 x – 5)
therefore,
<span>A =
(2 x – 5)^2 </span>
Expanding,
A =
4 x^2 – 20 x + 25
<span>B.
The degree of a polynomial is the highest exponent of the variable x, in this case
2. Therefore the expression obtained in part A is of 2nd degree.</span>
Furthermore,
polynomials are classified according to the number of terms in the expression.
There are 3 terms in the expression therefore it is classified as a trinomial.
<span>C.
The closure property demonstrates that during multiplication or division, the
coefficients and power of the variables are affected while during
multiplication or division, only the coefficients are affected while the power
remain the same.</span>
We can readily know the x^2-4x+4=3y then use it to replace the same function in the first equation which refers to the 3y+y^2-6y=0
y^2-3y=0
y(y-3)=0
y1=0 -----------y2=3
