When you bisect something, you cut it into two equally sized pieces. (from Latin: "bi" = two, "sect" = cut)
Bisecting an interval creates two smaller intervals each with half the length of the original interval. Some examples:
• bisecting [0, 2] gives the intervals [0, 1] and [1, 2]
• bisecting [-1, 1] gives the intervals [-1, 0] and [0, 1]
• bisecting an arbitrary interval ![[a,b]](https://tex.z-dn.net/?f=%5Ba%2Cb%5D)
gives the intervals ![\left[a,\frac{a+b}2\right]](https://tex.z-dn.net/?f=%5Cleft%5Ba%2C%5Cfrac%7Ba%2Bb%7D2%5Cright%5D)
and ![\left[\frac{a+b}2,b\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7Ba%2Bb%7D2%2Cb%5Cright%5D)
Answer:
a.) 1/2
b.) 1/8
c.) 5/8
d.) 1/2
Step-by-step explanation:
for A it is asking for probability of 1 and is 1/2 of the circle
for B it is asking for probability of 3 and it is 1/2 of and 1/4 of the circle so 1/8
for C it is asking for probability of the odd numbers and there is tow odd numbers 1 and 3 the probability of 1 is 1/2 and the probability of 3 is 1/8 adding them up will give you 5/8
for d it asks for the probability of at least 2 so therefor 2, 3, and 4 and they are 1/8 + 1/8 + for 1/4 = 1/2
Step-by-step explanation:
General line equation: y = mx + c.
2y + 3x = 5
2y = -3x + 5
y = -1.5x + 2.5
Hence m = -1.5 and c = 2.5.
Answer:
The answer to your question is (2)(3)(11)
Step-by-step explanation:
Data
154
Process
1.- Find the prime factors of 154, starting with 2, then, 3, 5, 7, etc
154 2
77 7
11 11
1
2.- Write 154 as a composition of prime factors
154 = (2)(7)(11)
3.- Conclusion
The prime factors of 154 are 2, 3 and 11
