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2 years ago

Here are the test scores for 10 students in Mr. P's class.

Mathematics

1 answer:

lutik1710 [3]2 years ago

7 0

We need mean

$\\ \rm\hookrightarrow Mean=\dfrac{Sum}{n}$

$\\ \rm\hookrightarrow \dfrac{59+94+57+87+75+90+82+57+65+77}{10}$

$\\ \rm\hookrightarrow 74.3\%$

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Evaluate the expression for x = 2 and y = 4. Enter your answer in the box. 16x0 + 2x2 • y –1

swat32

Given that,

The given expression is : $16x^0+2x^2{\cdot}y^{-1}$

To find,

The value of the above expression when x = 2 and y = 4

Solution,

We have,

$16x^0+2x^2{\cdot}y^{-1}$

Put x = 2 and y = 4 in the above expression.

$16x^0+2x^2{\cdot}y^{-1}\\\\=16\times (2)^0+2(2)^2\times (4)^{-1}\\\\=16\times 1+2(2)^2\times\dfrac{1}{4}\\\\=16+2\\\\=18$

So, the value of the above expression is 18.

6 0

2 years ago

Which of the following is the solution to the inequality -2x-4 ≤ 11

Art [367]

Answer:

$x\geq -\frac{15}{2}$

Step-by-step explanation:

add 4 on both sides

leaves you with 15 on the right side

you then divide by negative 2

since you divide by a negative you have to switch the sign

4 0

3 years ago

Read 2 more answers

The radius of a semicircle is 3 feet. What is the semicircle's area? Use 3.14 for Pi

valentinak56 [21]

Answer:

14.13 ft²

Step-by-step explanation:

The area of a semicircle is

$= \frac{\pi \: {r}^{2} }{2}$

We were given the radius of the semicircle to be: r=3 feet.

We were also asked to use π as 3.14.

We substitute into the formula to get:

$= \frac{3.14 \times {3}^{2} }{2}$

This is the same as:

$= \frac{3.14 \times 9}{2}$

$= 3.14 \times 4.5$

$= 14 .13 {ft}^{2}$

The area of the semicircle is 14.13 ft²

5 0

3 years ago

The expression 8³⋅2−¹⁰ is equal to what? ᶠʳᵉᵉ ᵖᵒᶦⁿᵗˢ!! ᵃⁿᵈ ᶜᵘᵗᵉ ᵖᶦᶜᵗᵘʳᵉˢ ♡

ExtremeBDS [4]

The Awnser is 1/2 I think

8 0

3 years ago

Read 2 more answers

The mean percentange of a population of people eating out at least once a week is 57℅

Sidana [21]

Answer:

The correct answer is B. between 56.45% and 57.55%

Complete statement and question:

The mean percentage of a population of people eating out at least once a week is 57% with a standard deviation of 3.50%. Assume that a sample size of 40 people was surveyed from the population a significant number of times. In which interval will 68% of the sample means occur?

between 55.89% and 58.11%

between 56.45% and 57.55%

between 56.54% and 57.46%

between 56.07% and 57.93%

Source: brainly.com/question/1068489

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Mean percentage of a population of people eating out at least once a week = 57%

Standard deviation = 3.5%

Sample size = 40

Confidence level = 68%

2. In which interval will 68% of the sample means occur?

For answering this question, we should find out the standard deviation of the sample, using this formula:

Standard deviation of the sample = Standard deviation of the population/√Sample size

Standard deviation of the sample = 3.5/√40

Standard deviation of the sample = 3.5/6.32

Standard deviation of the sample = 0.55

Let's recall that a confidence level of 68% means that 68% of the sample data would have a value between the mean - 1 time the standard deviation of the sample and the mean + 1 time the standard deviation of the sample. Thus:

57 - 1 * 0.55 = 57 - 0.55 = 56.45

57 + 1 * 0.55 = 57 + 0.55 = 57.55

The correct answer is B. between 56.45% and 57.55%

7 0

3 years ago