Question

Special Right Trianglws

Answer 1

Answer:

x = $2\sqrt7$

y = $2\sqrt7$

Step-by-step explanation:

Hello!

This is a right isosceles triangle (45°-45°-90°). You can solve for the missing angle by simply subtracting 45° and 90° from 180° (sum of angles in a triangle equals 180°)

Since the triangle is isosceles, x and y are congruent because they are the legs opposite to the congruent angles.

In a right isosceles triangle, the hypotenuse is always the measure of one leg multiplied by $\sqrt2$.

So, let's use leg y, $y\sqrt2 = 2\sqrt{14}$

Solve for y:

$y\sqrt2 = 2\sqrt{14}\\\\y = \frac{2\sqrt{14}}{\sqrt2} \\\\y = 2\sqrt7$

y = $2\sqrt7$, which means that x is also $2\sqrt7$