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bezimeni [28]
2 years ago
11

Special Right Trianglws

Mathematics
1 answer:
Masteriza [31]2 years ago
3 0

Answer:

x = 2\sqrt7

y = 2\sqrt7

Step-by-step explanation:

Hello!

This is a right isosceles triangle (45°-45°-90°). You can solve for the missing angle by simply subtracting 45° and 90° from 180° (sum of angles in a triangle equals 180°)

Since the triangle is isosceles, x and y are congruent because they are the legs opposite to the congruent angles.

In a right isosceles triangle, the hypotenuse is always the measure of one leg multiplied by \sqrt2.

So, let's use leg y, y\sqrt2 = 2\sqrt{14}

Solve for y:

y\sqrt2 = 2\sqrt{14}\\\\y = $\frac{2\sqrt{14}}{\sqrt2}$\\\\y = 2\sqrt7

y = 2\sqrt7, which means that x is also 2\sqrt7

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Hope this helps? :)

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