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Sidana [21]
1 year ago
11

erika needs a test average of 85 or higher to make the honor roll there are four tests in the term her first three test grades 7

8,80,and 88. which inequality could be used to find what she needs to score on her fourth test, x, in order to make the honor roll
Mathematics
1 answer:
jenyasd209 [6]1 year ago
5 0

First, notice that we want the average to be 85 or higher. We can write this like this:

\mu\ge85

where mu is the average.

We know that there are four tests, and there are already three grades: 78,80 and 88. Then if we calculate the mean we have:

\begin{gathered} \mu=\frac{78+80+88+x}{4}=\frac{x+246}{4} \\ \Rightarrow\mu=\frac{x+246}{4} \end{gathered}

but we already know that the average must be greater or equal than 85, then, combining both expressions we get the following:

\begin{gathered} 85\le\mu=\frac{x+246}{4} \\ \Rightarrow\frac{x+246}{4}\ge85 \end{gathered}

solving the inequality for x, we get:

\begin{gathered} \frac{x+246}{4}\ge85 \\ \Rightarrow x+246\ge85\cdot4=340 \\ \Rightarrow x\ge340-246=94 \\ x\ge94 \end{gathered}

therefore, Erika needs a score of 94 or higher in order to make the honor roll

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Answer:

The margin of error is 6.45.

Step-by-step explanation:

The complete question is:

As an early intervention effort, a school psychologist wants to estimate the average score on the Stanford-Binet Intelligence Scale for all students with a specific type of learning disorder using a simple random sample of 36 students with the disorder.

Determine the margin of error, of a 99% confidence interval for the mean IQ score of all students with the disorder. Assume that the standard deviation IQ score among the population of all students with the disorder is the same as the standard deviation of IQ score for the general population, σ = 15 points.

The (1 - <em>α</em>)% confidence interval for population mean <em>μ</em> is:

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The margin of error for this interval is:

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Given:

<em>n</em> = 36

σ = 15

(1 - <em>α</em>)% = 99%

Compute the critical value of <em>z</em> for 99% confidence level as follows:

z_{\alpha/2}=z_{0.01/2}=z_{0.005}=2.58

*Use a <em>z</em>-table.

Compute the value of MOE as follows:

MOE= z_{\alpha/2}\times\frac{\sigma}{\sqrt{n}}

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Thus, the margin of error is 6.45.

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Step-by-step explanation:

Let's solve your equation step-by-step.

−5(x+4)=70

Step 1: Simplify both sides of the equation.

−5(x+4)=70

(−5)(x)+(−5)(4)=70(Distribute)

−5x+−20=70

−5x−20=70

Step 2: Add 20 to both sides.

−5x−20+20=70+20

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Step 3: Divide both sides by -5.

−5x

−5

=

90

−5

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