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sweet [91]
3 years ago
7

Exercise 2 Determine the measures of the angles marked with letters. (Note: Lines with arrowheads are parallel)

Mathematics
1 answer:
-Dominant- [34]3 years ago
6 0

Answer: n⁰ = 70⁰

Ok done. Thank to me :>

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Easy way to remember my 9th multiplication chart
kap26 [50]
If you wanna divide 9's on your fingers, its really easy...
Example: If you wanna do 3x9 you hold up your 10 fingers and put down your fourth finger... it would look like your saying 36, and that is your answer. 
Another example:  If you wanna do 6x9 you hold up your 10 fingers and put down your 7th finger... It would look like you are saying 63 and that is your answer.
I hope this helps, tell me if you have any questions.<span />
8 0
3 years ago
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X plus 4x plus 6x simplified
erica [24]

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the answer is 11x. just add everything together.

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F(n) = 2n− 5; Find f(−8)
scoundrel [369]

Answer:

Step-by-step explanation:

Putting value of n = - 8 in the equation

F(n) = 2n− 5

F(-8) = 2(-8) - 5

= - 16 - 5 = - 21

5 0
3 years ago
I really need help! Pls!
Alex
A1 is reflected across line x=-3. First option
5 0
3 years ago
The function f(h)=m(1/2)^h gives the mass, m, of a radioactive substance remaining after h half-lives. Cobalt-60 has a half-life
goldfiish [28.3K]

Answer:

Third choice:

                f(x)=50(0.877)^{10};13.5mg

Explanation:

<u />

<u>1. Data:</u>

<u />

  • Function:

                f(h)=m(1/2)^h

  • Cobalt-60's half-life: 5.3 years

  • Initial mass of cobalt-60:  50 mg

<u>2. Unknown: </u>

<u />

  • equation for the mass of cobalt-60 remaining after 10 years = ?

  • mass remaining =?

<u>3. Solution</u>

<em>Half-life</em> is the time it takes a sample to  decay to half of its initial amount. It is considered constant. Hence, when one half-life passes, the sample has decayed to 50% of the original amount; when two half-lives pass, the sample has decayed to (1/2)×(1/2) = 1/4 = 25%; when three half-lives have elapsed, the sample has decayed to (1/2)³ = 1/8 = 12.5% of its original amount, and so on.

Then, the amound of a sample remaining is calculated as the original amount times (1/2) raised to the number of half-lives elapsed, which is what the given function,  f(h)=m(1/2)^h models.

You just must substitute the data into the function to get the answer to the question:

            f(x)=50(0.5)^{(10/5.3)}

Where, 50 is the original mass of 50g, 0.5 is equal to 1/2, and 10/5.3 gives the number of half-lives (the number of times that 5.3 years is contained in 10 years).

<u>Simplifying:</u>

f(x)=50(0.5)^{(10/5.3)}=50((0.5)^{(1/5.3})^{10}\approx50(0.877)^{10}

Which corresponds to the third choice of the list.

<u>Computing:</u>

               f(x)\approx50(0.877)^{10}=13.5

Which also corresponds to the third choice.

4 0
3 years ago
Read 2 more answers
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