Find the area of the polygon. Figure ABCDE is shown. A is at 6, 0. B is at negative 4, 5. C is at 2, 5. D is at 2, 9. E is at 6,
9. 41 square units 44 square units 52 square units 56 square units
1 answer:
This question is incomplete. The attached image was obtained online
Answer:
41 square units
Step-by-step explanation:
Looking at diagram that was attached, we can see that the Polygon s the combination of a square and a triangle.
In square CDEF we have:
The lengths of the side of the square= 4 units
Hence, the area of square is: length ²
Area of square= 4²
=16 square units
Also, in ΔBFA we have:
The base of the triangle is calculated as
=6 + 4= 10 units
height of the triangle is: FA= 5 units
The formula for Area of a triangle = 1/2 × Base × Height
Hence, we have area of ΔBFA as:
= 1/2 × 10 × 5
Area= 25 square units
The Area of the Polygon = Area of the square + Area of the triangle
16 square units + 25 square units
= 41 square units
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<u>Answer-</u> Length of the curve of intersection is 13.5191 sq.units
<u>Solution-</u>
As the equation of the cylinder is in rectangular for, so we have to convert it into parametric form with
x = cos t, y = 2 sin t (∵ 4x² + y² = 4 ⇒ 4cos²t + 4sin²t = 4, then it will satisfy the equation)
Then, substituting these values in the plane equation to get the z parameter,
cos t + 2sin t + z = 2
⇒ z = 2 - cos t - 2sin t
∴
As it is a full revolution around the original cylinder is from 0 to 2π, so we have to integrate from 0 to 2π
∴ Arc length
Now evaluating the integral using calculator,
