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3 years ago

Negative solution for Multi-step equations

Mathematics

1 answer:

nydimaria [60]3 years ago

3 0

Answer:

$\frac{1}{2}(4x+6)+3x=7x+9$

$\frac{1}{2}(4x+8)+3x=7x+9$

Step-by-step explanation:

By putting the numbers in the given equation,

$\frac{1}{2}(4x+6)+3x=7x+9$

2x + 3 + 3x = 7x + 9

5x + 3 = 7x + 9

(5x + 3) - 7x = (7x + 9) - 7x

(5x - 7x) + 3 = 9

-2x + 3 = 9

(-2x + 3) - 3 = 9 - 3

-2x = 6

$-\frac{2x}{2}=\frac{6}{2}$

-x = 3

x = -3

Therefore, our equation is correct which has a negative result.

In place of 6 if we use 8, value of x will be negative again.

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In the diagram, the radius of the outer circle is 2x cm and the radius of the inside circle is 6 cm. The area of the shaded regi

Alexeev081 [22]

The area of a circle is πr²
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3 years ago

According to The Wedding Report, Inc., the mean cost for a wedding in the United States is $28732 (as of November 2008). Suppose

Stella [2.4K]

Answer:

Following are the solution to the given points:

Step-by-step explanation:

$X = \text{cost of wedding}\sim \text{Normal}\ (\mu = 28732, \sigma= 1500)\\\\$

For point a:

$Probability\ = 0.00000359\\\\ \text{(Using Excel function:} =NORMDIST(22000,28732,1500,1)).$

For point b:

$Probability \ = 0.014678\\\\\text{(Using Excel function:} =1-NORMDIST(32000,28732,1500,1))\\\\$

For point c:

$Probability\ = 0.794614436 \\\\$

$\text{(Using Excel function:} \\=NORMDIST (30000,28732,1500,1)-NORMDIST(25000,28732,1500,1))\\\\$

For point d:

$Q_1 = 27720.26537 \\\\\text{(Using Excel function:} =NORMINV(0.25,28732,1500)) \\\\Q_3 = 29743.73463 \\\\\text{(Using Excel function:} =NORMINV(0.75,28732,1500)).$

For point e:

$IQR = Q_3 - Q_1 = 29743.73463 - 27720.26537 = 2023.469251.$

For point f:

$Top\ 10\% = 30654.32735 \\\\\text{(Using Excel function:} =NORMINV(0.9,28732,1500)).$

5 0

3 years ago

Really need help with this pls help!!

worty [1.4K]

Let's carry this math sentence over to its natural, "shapey" element. We're going to look at each term not as an ordinary number, but as the area of some shape.

x² (read as "x squared") can be seen as the area of a square with side lengths of x. 2x can similarly be seen as the area of a rectangle with a length of x and a width of 2. (Picture 1)

What's our question actually asking, though? Something about perfect squares. More specifically, we're looking for something to add on that'll make this thing a perfect square. We're trying to find a missing piece we can slot in to make a square, in other words. Problem is, our shapes don't look much like a square if we put them together right now. We need to do a little cutting and gluing first.

First, we're gonna cut the 2x rectangle lengthwise, getting two rectangles with an area of x, a length of 1, and a width of x. Next, we're going to attach them to the x² square, creating this shape that looks, strangely, like a square with a little bit missing from it (picture 2). What we're trying to do is complete this square, to find the area of that little missing chunk.

As it turns out, we have all the information we need for this. Notice that, using the lengths of the x rectangles, we can find that the square's dimensions are 1 x 1, which means that its area is 1 x 1 = 1.

If we tack this new area on to our original expression, we've "completed the square!" We now have a perfect square with side lengths of (x + 1) and an area of (x + 1)² (picture 3).

So, our final expression is x² + 2x + 1, and the missing constant - the area of the "missing square" we had to find to complete our larger one - is 1.