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2 years ago

Calculate the kinetic energy of a boy of mass 65kg running with average speed of 20m/s (3mks)

Mathematics

1 answer:

lesya692 [45]2 years ago

3 0

<h3>Answer: 13000 joules</h3>

This is equivalent to 13 kilojoules.

=======================================================

Work Shown:

m = 65 kg = mass

v = 20 m/s = velocity

KE = kinetic energy

KE = (1/2)*m*v^2

KE = (1/2)*65*(20)^2

KE = 13000 joules

This can be written as 13 kilojoules since "kilo" means "1 thousand"

The abbreviation of the unit "joules" is the letter J.

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Y = 7/8u + 9, solve for u

vivado [14]

Answer:

$u=\frac{8y-72}{7}$

Step-by-step explanation:

Flip the equation.

$\frac{7}{8}u+9=y$

Add -9 to both sides

$\frac{7}{8}u+9(-9)=y(-9)$

$\frac{7}{8}u=y-9$

Divide both sides by 7/8

$u=\frac{8y-72}{7}$

hope this helps

3 0

3 years ago

PLEASE PLEASE PLEASE ANSWER ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

gtnhenbr [62]

The answer is times the 5500 adding the 6600 and as it adds up the box rate to 1.75 the answer is 1.75 insterest rate and 132000 dollars left

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3 years ago

Read 2 more answers

In Exercises 23–36, solve the system using either Gaussian elimina- tion with back-substitution or Gauss-Jordan elimination. 23.

Luba_88 [7]

Answer:

23) x= 3, y = 4

24) Any (x,y) values where x = 1.5 - 2y

Step-by-step explanation:

For the first system(23), it goes like this

[1 2 | 7]

[2 1 | 8]

We need to do L2 = L2 - 2L1, so now it is

[1 2 | 7]

[0 -3 |-6]

So, now we have:

-3y = -6 *(-1)

3y = 6

y = 2

x + 2y = 7

x + 4 = 7

x = 3

Now for system 24, we have:

[-1 2 | 1.5]

[2 -4| 3]

We do L2 = L2 + 2L1, so we have:

[-1 2 | 1.5]

[0 0| 0]

So there are infinite solutions for this system. The solution for this system will be each (x,y) pair where x = 1.5 - 2y.

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3 years ago

Simplify each expression<br>4sg/-5g<br>and<br>(8 + 7a) + 4

Yanka [14]

$\dfrac{4sg}{-5g}=-\dfrac{4}{5}\cdor\dfrac{sg}{g}=-\dfrac{4}{5}s\\\\(8+7a)+4=7a+(8+4)=7a+12$

5 0

2 years ago

Part C

makkiz [27]

a = 1, b =14 and y-coordinate is 6 when x = 0.

Solution:

Let us first write the equation of a line.

Take the points are (2, 2) and (6, 10).

Slope of the line:

$$m=\frac{y_2-y_1}{x_2-x_1}$

$$m=\frac{10-2}{6-2}$

$$m=\frac{8}{4}$

m = 2

Point-slope formula:

$y-y_1=m(x-x_1)$

y - 10 = 2(x - 2)

y - 10 = 2x - 4

Add 10 on both sides,we get

y = 2x + 6

Equation of a line is y = 2x + 6.

To find (a, 8), substitute x = a and y = 8 in the equation,

8 = 2a + 6

Subtract 6 from both sides, we get

2 = 2a

a = 1

To find (4, b), substitute x = 4 and y = b in the equation,

b = 2(4) + 6

b = 8 + 6

b = 14

Substitute x = o in the equation.

y = 2(0) + 6

y = 6

The y-coordinate is 6 when x = 0.

7 0

3 years ago