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Bad White [126]
2 years ago
7

Part C

Mathematics
1 answer:
makkiz [27]2 years ago
7 0

a = 1, b =14 and y-coordinate is 6 when x = 0.

Solution:

Let us first write the equation of a line.

Take the points are (2, 2) and (6, 10).

Slope of the line:

$m=\frac{y_2-y_1}{x_2-x_1}

$m=\frac{10-2}{6-2}

$m=\frac{8}{4}

m = 2

Point-slope formula:

y-y_1=m(x-x_1)

y - 10 = 2(x - 2)

y - 10 = 2x - 4

Add 10 on both sides,we get

y = 2x + 6

Equation of a line is y = 2x + 6.

To find (a, 8), substitute x = a and y = 8 in the equation,

8 = 2a + 6

Subtract 6 from both sides, we get

2 = 2a

a = 1

To find (4, b), substitute x = 4 and y = b in the equation,

b = 2(4) + 6

b = 8 + 6

b = 14

Substitute x = o in the equation.

y = 2(0) + 6

y = 6

The y-coordinate is 6 when x = 0.

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dlinn [17]
ANSWER

The solution is
(-4,-1)


EXPLANATION

The given equations are:

2x + 5y =  - 13...(1)

and

3x - 4y =  - 8...(2)


We multiply equation 1 by 3 to get,

6x + 15y =  - 39...(3)

We multiply equation 2 also by 2 to get,

6x - 8y =  - 16...(4)

We subtract equation 4 from equation 3 to get,


23y =  - 23
This implies that,

y =  - 1

We put this value of y into any of the equations say equation 2

3x - 4( - 1) =  - 8
Simplify

3x + 4 =  - 8
Group like terms
3x =  - 8 - 4
Simplify,

3x =  - 12

Divide both sides by 3 to get,

x =  - 4


Therefore the solution is
(-4,-1)

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