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Drupady [299]
3 years ago
9

F(x) = x4/5(x − 6)2 find the critical numbers of the function

Mathematics
1 answer:
Fiesta28 [93]3 years ago
5 0
You can find the critical numbers by finding the derivative of the function and solving for 0.

F(x) = x(4/5)(x-6)(2) = x(8/5)(x-6) = (8/5)(x^2 - 6x)

Taking the derivative:
F'(x) =  (8/5)(2x - 6)
F'(x) = 0 at x = 3, 

critical number = 3
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Please answer both with work,please use a paper and picture, thanks ​
Irina-Kira [14]

Answer:

a.  $ \frac{\textbf{17}}{\textbf{4}} $

b.  $ \frac{\textbf{3}}{\textbf{8}} $

Step-by-step explanation:

a. $ \textbf{3} \hspace{1mm} \textbf{+} \hspace{1mm} \textbf{1}\frac{\textbf{1}}{\textbf{4}} $

A mixed fraction of the form $ a\frac{x}{y} = a + \frac{x}{y} $

$ \therefore 3 + 1\frac{1}{4} = 3 + 1 + \frac{1}{4} $

$ = 4 + \frac{1}{4} $

$ = \frac{\textbf{17}}{\textbf{4}} $

b. $ \textbf{2} \hspace{1mm} \textbf{-} \hspace{1mm} \textbf{1}\frac{\textbf{5}}{\textbf{8}} $

A mixed fraction of the form $ -c\frac{a}{b} = - c - \frac{a}{b} $

$ \therefore 2 - 1\frac{5}{8} = 2 - 1 - \frac{5}{8} $

$ = 1 - \frac{5}{8} $

$ = \frac{8 - 5}{8} $

$ = \frac{\textbf{3}}{\textbf{8}} $

Hence, the answer.

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