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3 years ago

Elapsed time 9 3/4 hours end time 6:00 p.m. what is the start time

1 answer:

4 0

It will be 8:15 am because if you start at 8:15 am and you add 9 hours 45 minutes you get 18 and the 18 hours of the day its 6:00 pm

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Factor out the common terms 6m - 21p

Ivenika [448]

Answer:3(2m-7p)

Step-by-step explanation:

you just divide each number by a common factor

4 0

3 years ago

Find the value of x. 54 79

Blababa [14]

Answer:

I believe it is 47 degrees

Step-by-step explanation:

Triangles add up to 180 degrees

54 + 79 = 133

180 - 133 = 47

4 0

3 years ago

The surface area of a cube is 6 square centimeters. What is its volume, in cubic centimeters?

Elenna [48]

Answer:

1 cubic centimeter is the volume

Step-by-step explanation:

the surface area is 6

6 = 6a^2

1 = a^2

1 = a

L * W * H = ?

1 x 1 x 1 = 1

1 is the volume

have a good day!

3 0

3 years ago

A parabola can be drawn given a focus of (6,0) and a directrix of y = -6. Write the

VLD [36.1K]

Answer:

Equation of the parabola: $12y+36=(x-6)^2$ or $y=\frac{x^2}{12} -x$

Vertex form: $y=\frac{1}{12} (x-6)^2-3$

Intercept form: $y=\frac{x}{12} (x-12)$

Step-by-step explanation: hope this helps please give brainlieat!

7 0

3 years ago

Read 2 more answers

the pitch, or frequency, of a vibrating string varies directly with the square root of the tension. if a string vibrates at a fr

Naily [24]

$\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\
\begin{array}{llll}
\stackrel{frequency}{f}\textit{ of a vibrating string varies directly}\\
\qquad \qquad \textit{with the square root of the tension }\stackrel{tension}{t}
\end{array}$

$\bf f=k\sqrt{t}\quad \textit{we also know that }
\begin{cases}
f=300\\
t=8
\end{cases}\implies 300=k\sqrt{8}
\\\\\\
\cfrac{300}{\sqrt{8}}=k\implies \cfrac{300}{\sqrt{2^2\cdot 2}}=k\implies \cfrac{300}{2\sqrt{2}}=k\implies \cfrac{150}{\sqrt{2}}=k
\\\\\\
\textit{and we can \underline{rationalize} it to }\cfrac{150\sqrt{2}}{2}\implies 75\sqrt{2}=k$

$\bf thus\qquad f=\stackrel{k}{75\sqrt{2}}\sqrt{t}\implies \boxed{f=75\sqrt{2t}}\\\\
-------------------------------\\\\
\textit{now, when t = 72, what is \underline{f}?}\qquad f=75\sqrt{2(72)}$

5 0

3 years ago

Read 2 more answers