1600 children and 1400 adults attended
<h3>How to determine the number of adults?</h3>
Let the children be x and adult be y.
So, we have the following equations:
x + y = 3000
1.5x + 5y = 9400
Make x the subject in x + y = 3000
x = 3000 - y
Substitute x = 3000 - y in 1.5x + 5y = 9400
1.5(3000 - y) + 5y = 9400
Expand
4500 - 1.5y + 5y = 9400
Evaluate the like terms
3.5y = 4900
Divide both sides by 3.5
y = 1400
Substitute y = 1400 in x = 3000 - y
x = 3000 - 1400
Evaluate
x = 1600
Hence, 1600 children and 1400 adults attended
Read more about system of equations at:
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Answer:
33.33 percent are not riding the bus
Step-by-step explanation:
Answer:
![\frac{ \sqrt[3]{x} }{9}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%20%5Csqrt%5B3%5D%7Bx%7D%20%20%7D%7B9%7D%20)
Quotient means the answer after dividing two numbers.
Answer:
We have been given that PQ bisects . In the second statement of the given two-column proof, the statement is .
This implies that the two angles formed by bisection of angle by the line PQ are equal. We know that the reason for this is simple. It is the definition of bisection of an angle that the two smaller angles formed will be equal to each other.
Therefore, the reason for statement 2 of the given two column proof is c) Definition of bisect
Step-by-step explanation:
Answer:
Given:
n = 550
Po = 51% = 0.51
P0 - 1 = 0.51 - 1 = 0.49
p' = 
= 0.5218
np0(1 - p0) = 550*0.51(1-0.51)
= 137.4 ≥ 100
This means the sample size is greater than 5% of the population size. and the sample can be reasonably assumed to be random, the requirement for testing hypothesis are satisfied.
1) The null and alternative hypotheses:
H0 : p0 = 0.51
H1 : p0 ≠ 0.51
The test statistic Z,
Z = 0.55
This is two tailed test.
The pvalue for Z =0.55
Pvalue = 0.5824
3) Decision:
Since pvalue, 0.5824 is greater than significance level, we fail to reject null hypothesis H0.
Conclusion:
Do not reject Upper H0. There is not sufficient evidence at the alpha equals 0.01 level of significance to conclude that the proportion of females who are living alone has changed.
