1 yard = 3 feet
40 ÷ 3 = 13.33...
Round and it is near 13 yards
Answer:
The answer is option D
32 + (4c − 6c) + (2 + 6c)
c = 5
32 + ( 4(5) - 6(5)) + (2 + 6 (5)
= 32 + (20 - 30) + ( 2 + 30)
= 32 - 10 + 32
= 54
Hope this helps
ANSWER
![2v + u = \binom{5}{15}](https://tex.z-dn.net/?f=2v%20%2B%20u%20%3D%20%5Cbinom%7B5%7D%7B15%7D)
EXPLANATION
It was given that:
![u = \binom{1}{3}](https://tex.z-dn.net/?f=u%20%3D%20%20%5Cbinom%7B1%7D%7B3%7D%20)
and
![v = \binom{2}{6}](https://tex.z-dn.net/?f=v%20%3D%20%20%5Cbinom%7B2%7D%7B6%7D%20)
![2v + u =2 \binom{2}{6} + \binom{1}{3}](https://tex.z-dn.net/?f=2v%20%2B%20u%20%3D2%20%20%5Cbinom%7B2%7D%7B6%7D%20%20%2B%20%20%5Cbinom%7B1%7D%7B3%7D%20)
Perform the scalar multiplication to obtain:
![2v + u = \binom{4}{12} + \binom{1}{3}](https://tex.z-dn.net/?f=2v%20%2B%20u%20%3D%20%5Cbinom%7B4%7D%7B12%7D%20%20%2B%20%20%5Cbinom%7B1%7D%7B3%7D%20)
We add the corresponding components to get;
![2v + u = \binom{4 + 1}{12 + 3}](https://tex.z-dn.net/?f=2v%20%2B%20u%20%3D%20%5Cbinom%7B4%20%2B%201%7D%7B12%20%2B%203%7D)
![2v + u = \binom{5}{15}](https://tex.z-dn.net/?f=2v%20%2B%20u%20%3D%20%5Cbinom%7B5%7D%7B15%7D)
The first choice is correct.
9514 1404 393
Answer:
- 13 ft
- (a) 1 second; (b) t = 0, t = 1/2
Step-by-step explanation:
<h3>1. </h3>
Let w represent the length of the wire. Then the height of attachment is (w-1). The Pythagorean theorem tells us a relevant relation is ...
5² +(w -1)² = w²
w² -2w +26 = w² . . . . . . . eliminate parentheses, collect terms
26 = 2w . . . . . . . . . . . . add 2w
13 = w . . . . . . . . . . . . divide by 2
The length of the wire is 13 feet.
__
<h3>2. </h3>
(a) When h = 0, the equation is ...
0 = -16t^2 +8t +8
Dividing by -8 puts this into standard form:
2t^2 -t -1 = 0
Factoring, we get ...
(2t +1)(t -1) = 0
The positive value of t that makes a factor zero is t = 1.
It will take 1 second for the gymnast to reach the ground.
__
(b) When h = 8, the equation is ...
8 = -16t^2 +8t +8
Subtract 8 and divide by 8 to get ...
0 = -2t^2 +t
0 = t(1 -2t) . . . . factor out t
Values of t that make the factors zero are ...
t = 0
t = 1/2
The gymnast will be 8 feet above the ground at the start of the dismount, and 1/2 second later.
Answer:
The fraction would be 35/100.
If you want to simplify it would be 7/20.
Hope this helps!
Please mark me brainliest if I am correct! Thank you and have a nice day!
Step-by-step explanation: