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scoundrel [369]
2 years ago
14

Help please Gina Wilson 8.3

Mathematics
1 answer:
Alex73 [517]2 years ago
7 0

Answer:

Pls find the given attachment

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What is the cube root of 27a^12
tino4ka555 [31]

ANSWER

3{a}^{4 }

EXPLANATION

The cube root of

27 {a}^{12}

is

\sqrt[3]{27 {a}^{12} }

This is the same as:

(27 {a}^{12} )^{ \frac{1}{3} }

( {3}^{3} ({a}^{4})^{3}  )^{ \frac{1}{3} }

=  (3{a}^{4} )^{3 \times  \frac{1}{3} }

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3 years ago
What is the average of 74 and 57?
Lina20 [59]

Answer:

65.5

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
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3. find the domain and range of <br>a) 3x-2y+7=0<br>i think in y-intercept form it is y=3/2x + 7/2
bekas [8.4K]
3x-2y+7=0\\\\The\ slope-intercept\ form:\\\\2y=3x+7\ \ \ \ \ /:2\\\\y=\frac{3}{2}x+\frac{7}{2}\\\\The\ domain:x\in\mathbb{R}\\\\The\ range:y\in\mathbb{R}

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Sergio [31]

Answer:

In order of the paragraph:

3, isosceles, greater, 3 in

Step-by-step explanation:

The first drop box has to be 3 because if you add up two sides of a triangle, the sum has to be greater than the third side. If two sides are equal, the triangle is isosceles. The third side cannot be 1 since 1+1 is not greater than 3. So the third side must measure 3in.

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