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nadya68 [22]
2 years ago
11

Plssss answer… for math

Mathematics
2 answers:
Mademuasel [1]2 years ago
7 0
Graph A is a function and graph B isn’t a function
Greeley [361]2 years ago
4 0

Answer:

Graph A is a function, and Graph B is not

Step-by-step explanation:

A function is when each x-value (aka input) has 1 corresponding y-value (or output).

We see that graph 1 is linear, and that each x-value has it's own y-value, and not multiple y-values.

However, Graph B curves, making it so some of the x-values have more than 1 y-value.

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Which equation is equivalent to 3[x+3(4x-5)]=15x-24
Klio2033 [76]
3[x+3(4x-5)]=15x-24; x+12x-15=5x-8 (divide both sides by 3); 8x=7 (move all the x's to one side), x=7/8
7 0
3 years ago
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On a vacation trip to Canada you realize that the speed limit signs are in km/hour. Unfortunately, your speedometer only reads i
Annette [7]

Answer:

120 km is 74.56 miles so just round that

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3 years ago
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Help???????????????????
Reil [10]

Answer:

42:36

=42/36

=(7*6)/(6*6)

=7/6

Step-by-step explanation:

4 0
2 years ago
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Given that (-4,-4) is on the graph of f(x), find the corresponding point for the function 1/2 f(x)
marusya05 [52]

Answer:

(-4, -2)

Step-by-step explanation:

The x-coordinate would stay the same, but the y-coordinate would be halved.  Thus, the corresponding point would be (-4, -2).

3 0
3 years ago
Write an indirect proof showing that the diagonals of a parallelogram intersect each other
____ [38]
Its an indirect proof, so 3 steps :-
1) you start with the opposite of wat u need to prove 
2) arrive at a contradiction
3) concludeReport · 29/6/2015261
since you wanto prove 'diagonals of a parallelogram bisect each other', you start wid the opposite of above statement, like below :- step1 : Since we want to prove 'diagonals of a parallelogram bisect each other', lets start by assuming the opposite, that the diagonals of parallelogram dont bisect each other.Report · 29/6/2015261


Since, we assumed that the diagonals dont bisect each other, 
OC≠OA 
OD≠OBReport · 29/6/2015261
Since, OC≠OA, △OAD is not congruent to △OCBReport · 29/6/2015261

∠AOD≅∠BOC as they are vertical angles, 
∠OAD≅∠OCB they are alternate interior angles 
AD≅BC, by definition of parallelogram 
so, by AAS, △OAD is congruent to △OCBReport · 29/6/2015261
But, thats a contradiction as we have previously established that those triangles are congruentReport · 29/6/2015261
step3 :
since we arrived at a contradiction, our assumption is wrong. so, the opposite of our assumption must be correct. so diagonals of parallelogram bisect each other.
4 0
3 years ago
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