Im stuck i dont know how to answer

Mathematics

1 answer:

Sloan [31]2 years ago

5 0

I Think a or c hope this helps

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Suppose that y varies inversely with x.Write an equation for the inverse variation Y=4 when x=7

myrzilka [38]

Answer:

If y varies inversely as x, then we write it as:

y = k/x

where k is some constant.

If we multiply both sides of this equation by x we get an equation for k:

k = x*y

We are given that y=4 when x=7, therefore:

k = 7*4 = 28

Put this back into our original equation to get:

y = 28/x

4 0

3 years ago

Simplify (12a5−6a−10a3)−(10a−2a5−14a4) . Write the answer in standard form

almond37 [142]

Answer:

$=14a^5+14a^4-10a^3-16a$

Step-by-step explanation:

$\left(12a^5-6a-10a^3\right)-\left(10a-2a^5-14a^4\right)\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\=12a^5-6a-10a^3-\left(10a-2a^5-14a^4\right)\\-\left(10a-2a^5-14a^4\right):\quad -10a+2a^5+14a^4\\-\left(10a-2a^5-14a^4\right)\\\mathrm{Distribute\:parentheses}\\=-\left(10a\right)-\left(-2a^5\right)-\left(-14a^4\right)\\Apply\:minus-plus\:rules\\-\left(-a\right)=a,\:\:\:-\left(a\right)=-a\\=-10a+2a^5+14a^4\\=12a^5-6a-10a^3-10a+2a^5+14a^4$

$\mathrm{Simplify}\:12a^5-6a-10a^3-10a+2a^5+14a^4:\quad 14a^5+14a^4-10a^3-16a12a^5-6a-10a^3-10a+2a^5+14a^4\\Group\:like\:terms\\=12a^5+2a^5+14a^4-10a^3-6a-10a\\\mathrm{Add\:similar\:elements:}\:12a^5+2a^5=14a^5\\=14a^5+14a^4-10a^3-6a-10a\\\mathrm{Add\:similar\:elements:}\:-6a-10a=-16a\\=14a^5+14a^4-10a^3-16a$

4 0

3 years ago

According to a survey of adults, 64 percent have money in a bank savings account. If we were to survey 50 randomly selected adul

zheka24 [161]

Answer:

The mean number of adults who would have bank savings accounts is 32.

Step-by-step explanation:

For each adult surveyed, there are only two possible outcomes. Either they have bank savings accounts, or they do not. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

$E(X) = np$