PLS HELP ME WITH THISSSSSSSSSSS

Find three consecutive odd numbers whose sum is 1875.

masya89 [10]

Answer:

smaller number = 623

middle number = 625

larger number = 627

Step-by-step explanation:

Variable: X = smallest number

If these numbers are consecutive and odd, then the numbers would be:

x, x+2, x+4

x + (x + 2) + (x + 4)= 1875

3x + 6 = 1875

3x = 1869

x = 623

x + 2 = 625

x + 4 = 627

Check:

623 + 625 + 627 = 1875

4 0

2 years ago

5 -2x + 6y= -38 ? 3x – 4y = 32 •(-4, - 5) •(-5, 4) •(1, – 6) (4, - 5)

Svet_ta [14]

Answer:

Option D (4, -5)

Step-by-step explanation:

This question can be solved by various methods. I will be using the hit and trial method. I will plug in all the options in the both the given equations and see if they balance simultaneously.

Checking Option 1 by plugging (-4, -5) in the first equation:

-2(-4) + 6(-5) = -38 implies 8 - 30 = -38 (not true).

Checking Option 2 by plugging (-5, 4) in the first equation:

-2(-5) + 6(4) = -38 implies 10 + 24 = -38 (not true).

Checking Option 3 by plugging (1, -6) in the second equation:

3(1) - 4(-6) = 32 implies 3 + 24 = 32 (not true).

Since all the options except Option 4 have been ruled out, therefore, (4,-5) is the correct answer!!!

7 0

2 years ago

What is the equation of a line that has a slope of 2 and passes through the point (4,6) ?

natka813 [3]

Answer:

$y-6=2\,(x-4)$

or in slope y-intercept form :

$y=2x-2$

Step-by-step explanation:

The easiest way of find the answer for this is to use what is called the "point-slope" form of a line, because you are in fact given the value of the slope (m) and also a point $(x_0,y_0)$ it goes through:

$y-y_0=m\,(x-x_0)$

In our case the equation becomes:

$y-y_0=m\,(x-x_0)\\y-6=2\,(x-4)\\$

This can also be written in the slope-intercept form by solving for "y" and operating to remove the parenthesis:

$y-6=2\,(x-4)\\y=2x-8+6\\y=2x-2$

7 0

2 years ago

Mercury is a naturally occurring metal that can be harmful to humans. The current recommendation is for humans to take in no mor

kirill [66]

Answer:

A.) A person weights 80 kg can consume Haddock fish = 149 grams

B.) A person weights 80 kg can consume Swordfish fish = 8 grams

C.) A person weights 80 kg can consume Tuna fish = 23 grams

D.) A person weights 80 kg can consume Snapper fish = 50 grams

Step-by-step explanation:

Given - Mercury is a naturally occurring metal that can be harmful to humans. The current recommendation is for humans to take in no more than 0.1 microgram for every kilogram of their weight per day. Fish generally carry high levels of mercury, although certain fish have higher mercury content than others. Fish, however, are healthy sources of many other nutrients, so nutritionists recommend keeping them in the human diet. The figure below shows the average mercury content of several types of fish.

To find - If a person weighs 82 kg, how much of each fish can they safely consume? round to the nearest gram.

A.Haddock

B.Swordfish

C.Tuna

D.Snapper

Proof -

Firstly, determine how many micro grams of mercury a person can consume who weighs 82 kilograms.

⇒82 × 0.1 = 8.2 micro grams.

Now,

a.)

For Haddock fish-

It consumes 0.055 micro grams of mercury

So,

A person can consume fish = 8.2 ÷ 0.055

= 149.09 ≈ 149 grams

So,

A person weights 80 kg can consume Haddock fish = 149 grams

b.)

For Swordfish fish-

It consumes 0.995 micro grams of mercury

So,

A person can consume fish = 8.2 ÷ 0.995

= 8.24 ≈ 8 grams

So,

A person weights 80 kg can consume Swordfish fish = 8 grams

c.)

For Tuna fish-

It consumes 0.350 micro grams of mercury

So,

A person can consume fish = 8.2 ÷ 0.350

= 23.43 ≈ 23 grams

So,

A person weights 80 kg can consume Tuna fish = 23 grams

d.)

For Snapper fish-

It consumes 0.165 micro grams of mercury

So,

A person can consume fish = 8.2 ÷ 0.165

= 49.697 ≈ 50 grams

So,

A person weights 80 kg can consume Snapper fish = 50 grams

6 0

2 years ago

13. Evaluate * g(x) = x – 2x2 find g (1)

Trava [24]

Answer:

X= -1 or X= -3 . Probably the first one

Step-by-step explanation:

4 0

2 years ago