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saveliy_v [14]
3 years ago
5

Help i don't understand this please answer fast

Mathematics
1 answer:
Svetach [21]3 years ago
7 0

Answer:

B

Step-by-step explanation:

The Domain is the X- value so that makes it the domain and you have to order it correctly

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Don't know how to solve 6g+2 (-7+3g)=1-g
Nadya [2.5K]

Firstly, foil 2(-7 + 3g): 6g-14+6g=1-g

Next, combine like terms: 12g-14=1-g

Next, add g on both sides: 13g-14=1

Next, add 14 on both sides: 13g=15

Lastly, divide both sides by 13 and <u>your answer will be g=\frac{15}{13}=1\frac{2}{13}\approx 1.15</u>

6 0
3 years ago
One less than quotient of four and a number x
Bad White [126]

If all you want is just how this is written, then the answer is

\dfrac{4}{x} - 1

That's the way it reads. However you may have meant

\dfrac{x}{4} - 1

We cannot exactly tell from the wording what is meant. I would choose the first one, if this multiple choice. I would note the ambiguity if a person is doing the marking.

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3 years ago
Find the slope of the line through the following pair of points and draw the line through the points (4,1) (-1,-5)
Tresset [83]
Slope formula : (y2 - y1) / (x2 - x1)
(4,1)...x1 = 4 and y1 = 1
(-1,-5)...x2 = -1 and y2 = -5
now we sub and solve
slope = (-5 - 1) / (-1 - 4) = -6/-5 = 6/5 <==
7 0
4 years ago
Who wants 100 points? just answer this question… 9+10
Natali [406]

Answer:

=19

Step-by-step explanation:

What is the how many prime numbers are there from 100-110.

4 0
3 years ago
Read 2 more answers
the function f(t)= 3,500(1.003)^t gives the value of a saving account t months after it was opened.How long will it take for the
Pavel [41]

Answer:

After 19 months,value in the account will reach $3700

Step-by-step explanation:

The value of a savings account f(t) in terms of t ( number of months since account opening) is given as \[3,500(1.003)^{t}\]

We need to determine the value of t when f(t)>=3700

Expressing it in equation form,

\[3,500(1.003)^{t} >= 3700\]

\[=>(1.003)^{t} >= \frac{3700}{3500}\]

\[=>(1.003)^{t} >= 1.057\]

Taking log of both sides,

\[=>t * log(1.003) >= log(1.057)\]

\[=>t >= \frac{log(1.057)}{log(1.003)}\]

\[=>t >= 18.51\]

So t = 19.

6 0
3 years ago
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