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Sergio039 [100]
2 years ago
5

Write a cosine function that has a midline of 2, an amplitude of 4 and a period of pi/2.

Mathematics
1 answer:
exis [7]2 years ago
4 0

y = Acos(Bx) + D;

D = 4, A = 2. Now T = 2π/B = 5π/8, B = 2π/(5π/8) = 16/5

WE get y = 2cos(16/5x) + 4

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8 0
2 years ago
4 + 3s + 2<br> Terms:<br> Coefficients:<br> Constants:<br> Answer
USPshnik [31]

▬▬▬▬▬▬▬▬▬▬▬▬

<h3>4 + 3s + 2 </h3>

→ Terms - <u>Three</u> (<u>Trinomial</u>)

→ Coefficient - <u>3</u>

→ Constants - <u>4</u> and <u>2</u>

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8 0
3 years ago
What are the zeros of the graphed function y = (x + 3)(x + 5)?
tensa zangetsu [6.8K]
Y=(x+3)(x+5)
0=(x+3)(x+5)
0=x+3
Subtract three on both sides
-3=x
0=x+5
Subtract five on both sides
-5=x
So, -3 and -5 are the zeros of the graphed function.
Hope I helped!
5 0
3 years ago
Read 2 more answers
Plz answer this now anyone
bearhunter [10]

answer is f hope u like it plz mark me as brainliest plzzzzzzzzzzzzz

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2 years ago
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