My other answer was was lacking (I also believe I should have furthermore edited it.), therefore I will attempt to explain the steps correctly this time. I don't know what exactly is requested nor what you are learning, but I suspect it would be combinations, factorials, and/or permutations, something along those lines. Firstly I figured out my answer using factorials.
FROM: F,R,O,M. This obtains 4 letters.
4! (1 x 2 x 3 x 4)= 24
I am unsure if this is what you are looking for though. I hope this helped a bit.
Answer:
a) 658008 samples
b) 274050 samples
c) 515502 samples
Step-by-step explanation:
a) How many ways sample of 5 each can be selected from 40 is just a combination problem since the order of selection isn't important.
So, the number of samples = ⁴⁰C₅ = 658008 samples
b) How many samples of 5 contain exactly one nonconforming chip?
There are 10 nonconforming chips in the batch, and 1 nonconforming chip for the sample of 5 be picked from ten in the following number of ways
¹⁰C₁ = 10 ways
then the remaining 4 conforming chips in a sample of 5 can be picked from the remaining 30 total conforming chips in the following number of ways
³⁰C₄ = 27405 ways
So, total number of samples containing exactly 1 nonconforming chip in a sample of 5 = 10 × 27405 = 274050 samples
c) How many samples of 5 contain at least one nonconforming chip?
The number of samples of 5 that contain at least one nonconforming chip = (Total number of samples) - (Number of samples with no nonconforming chip in them)
Number of samples with no nonconforming chip in them = ³⁰C₅ = 142506 samples
Total number of samples = 658008
The number of samples of 5 that contain at least one nonconforming chip = 658008 - 142506 = 515502 samples
Answer:
P(I⋂D)
Step-by-step explanation:
The symbolic way to represent the probability of a true positive is P(I⋂D).
We know that I stands for Infected, U stands for Uninfected, D for Infection detected, N for infection no detected.
Then, a true positive will be given by the intersection of Infected and Infection Detected.
The Z- score representing the 99th percentile is given by 2.33
Problems of commonly distributed samples can be solved using the z-score formula.
For a set with a standard deviation, the z-score scale X is provided by:
Z = ( x- mean )/ standard deviation
Z-score measures how many standard deviations are derived from the description. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the scale is less than X, that is, the X percentage. Subtract 1 with p-value, we get the chance that the average value is greater than X.
To Find the z-result corresponding to P99, 99 percent of the normal distribution curve.
This is the Z value where X has a p-value of 0.99. This is between 2.32 and 2.33, so the answer is Z = 2.33
For more information regarding normal distribution, visit brainly.com/question/12691636
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22% = 22/100
22/100 * 14.50 = 3.19 (this is the amount discounted off original price)
14.50 - 3.19 = $11.31