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igor_vitrenko [27]
3 years ago
6

What is the imgae point of (-2,-3) after a translation right 2 units and 4 up units?​

Mathematics
1 answer:
kherson [118]3 years ago
5 0

the image point of (-2,-3) after a translation right 2 units and 4 up units is (0,1) .

<u>Step-by-step explanation:</u>

Here we have , to find  the image point of (-2,-3) after a translation right 2 units and 4 up units . Let's find out:

Initially we have the point as  (-2,-3) , Following transformations are done :

a translation right 2 units :

The point is (-2,-3)  , let (x,y)=(-2,-3) . Translation is 2 units right , means there is change in x coordinate by +2 , i.e.

⇒ (x,y)=(-2,-3)

⇒ (x+2,y)=(-2+2,-3)

⇒ (x+2,y)=(0,-3)

a translation  4 up units:

The point is (0,-3)  , let (x,y)=(0,-3) . Translation is 4 units up , means there is change in y coordinate by +4 , i.e.

⇒ (x,y)=(0,-3)

⇒ (x,y+4)=(0,-3+4)

⇒ (x,y+4)=(0,1)

Therefore , the image point of (-2,-3) after a translation right 2 units and 4 up units is (0,1) .

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Answer:

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Step-by-step explanation:

After consuming the energy drink, the amount of caffeine in Ben's body decreases exponentially.

This means that the amount of caffeine after t hours is given by:

A(t) = A(0)e^{-kt}

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The 10-hour decay factor for the number of mg of caffeine in Ben's body is 0.2722.

1 - 0.2722 = 0.7278, thus, A(10) = 0.7278A(0). We use this to find k.

A(t) = A(0)e^{-kt}

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We have to find find A(5), as a function of A(0). So

A(5) = A(0)e^{-0.03177289938*5}

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The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.

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