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igor_vitrenko [27]
3 years ago
6

What is the imgae point of (-2,-3) after a translation right 2 units and 4 up units?​

Mathematics
1 answer:
kherson [118]3 years ago
5 0

the image point of (-2,-3) after a translation right 2 units and 4 up units is (0,1) .

<u>Step-by-step explanation:</u>

Here we have , to find  the image point of (-2,-3) after a translation right 2 units and 4 up units . Let's find out:

Initially we have the point as  (-2,-3) , Following transformations are done :

a translation right 2 units :

The point is (-2,-3)  , let (x,y)=(-2,-3) . Translation is 2 units right , means there is change in x coordinate by +2 , i.e.

⇒ (x,y)=(-2,-3)

⇒ (x+2,y)=(-2+2,-3)

⇒ (x+2,y)=(0,-3)

a translation  4 up units:

The point is (0,-3)  , let (x,y)=(0,-3) . Translation is 4 units up , means there is change in y coordinate by +4 , i.e.

⇒ (x,y)=(0,-3)

⇒ (x,y+4)=(0,-3+4)

⇒ (x,y+4)=(0,1)

Therefore , the image point of (-2,-3) after a translation right 2 units and 4 up units is (0,1) .

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Answer:   \bold{b)\quad \dfrac{2\pi}{3},\dfrac{4\pi}{3},0}

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Note the following identities: tan² x = sec²x - 1

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