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2 years ago

Please help me with this and answer correctly pleaseeeeee!!!!!

Mathematics

1 answer:

Marta_Voda [28]2 years ago

5 0

Answer:

7 m

Explanation:

diameter = 12 m, radius = 6 m, volume of cone: $\sf \frac{1}{3} \pi r^2 h$

solve:

$\hookrightarrow \sf \frac{1}{3} \pi r^2 h = 264$

$\hookrightarrow \sf \frac{1}{3} \pi (6)^2 h = 264$

$\hookrightarrow \sf \pi (6)^2 h =792$

$\hookrightarrow \sf h =\dfrac{792}{ \pi (6)^2}$

$\hookrightarrow \sf h = 7$

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Answer:

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Step-by-step explanation:

4x² - 36x + 81 = 0
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Answer:

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Step-by-step explanation:

Let define some notation:

[L]= represent longitude , [T] =represent time

And we have defined:

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$v = \frac{ds}{dt}$

$a= \frac{dv}{dt}$

Part a

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$v = \frac{[L]}{[T]} = LT^{-1}$

Part b

For the acceleration we can use the result obtained from part a and we got:

$a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

Part c

From definition if we do the integral of the velocity respect to t we got the position:

$\int v dt = s(t)$

And the dimensional analysis for the position is:

$\int v dt = s(t) = [L]=L$

Part d

The integral for the acceleration respect to the time is the velocity:

$\int a dt = v(t)$

And the dimensional analysis for the position is:

$\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

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$\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

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