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2 years ago

Find the slope of a line parallel to y= -2/5x + 4/5 .

Mathematics

2 answers:

saul85 [17]2 years ago

6 0

Answer:

the slope is -2/5

Step-by-step explanation:

it did the question and got it right

Tatiana [17]2 years ago

5 0

Answer: m=45

Explanation:The slope of the line would be the same as in the equation (

) .

The only difference of a line running parallel would be the

value in

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Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.

likoan [24]

Answer:

Thus, the two root of the given quadratic equation $x^2+4=6x$ is 5.24 and 0.76 .

Step-by-step explanation:

Consider, the given Quadratic equation, $x^2+4=6x$

This can be written as , $x^2-6x+4=0$

We have to solve using quadratic formula,

For a given quadratic equation $ax^2+bx+c=0$ we can find roots using,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ ...........(1)

Where, $\sqrt{b^2-4ac}$ is the discriminant.

Here, a = 1 , b = -6 , c = 4

Substitute in (1) , we get,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$\Rightarrow x=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot 1 \cdot (4)}}{2 \cdot 1}$

$\Rightarrow x=\frac{6\pm\sqrt{20}}{2}$

$\Rightarrow x=\frac{6\pm 2\sqrt{5}}{2}$

$\Rightarrow x={3\pm \sqrt{5}}$

$\Rightarrow x_1={3+\sqrt{5}}$ and $\Rightarrow x_2={3-\sqrt{5}}$

We know $\sqrt{5}=2.23607$ (approx)

Substitute, we get,

$\Rightarrow x_1={3+2.23607}$ (approx) and $\Rightarrow x_2={3-2.23607}$ (approx)

$\Rightarrow x_1={5.23607}$ (approx) and $\Rightarrow x_2=0.76393}$ (approx)

Thus, the two root of the given quadratic equation $x^2+4=6x$ is 5.24 and 0.76 .

7 0

3 years ago

Read 2 more answers

If the area of a circle measures 25 cm?, what is the circumference of the circle in terms of ?

daser333 [38]

The correct answer is 5 cm

7 0

3 years ago

Which function has an asymptote at x= 39

LekaFEV [45]

Answer:

option B : $f(x)= log_7(x-39)$

Step-by-step explanation:

(a) $f(x) = 7^{x-39}$

For exponential function , there is no vertical asymptotes

General form of exponential function is

$f(x) = n^{ax-b}+k$

$f(x) = 7^{x-39}$

In the given f(x) the value of k =0

So horizontal asymptote is y=0

(b) lets check with option

$f(x)= log_7(x-39)$

To find vertical asymptote we set the argument of log =0 and solve for x

Argument of log is x-39

x-39=0 so x=39

Hence vertical asymptote at x=39

3 0

3 years ago

Read 2 more answers

Could someone help pls

Anna007 [38]

Answer:

40%

Step-by-step explanation:

6/15=favorable amount/total amount

6/15=2/5

2/5*20

8 0

3 years ago

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I need help please as soon as possible

blsea [12.9K]

Answer:

a. 86-degrees; angle-2 corresponds to the given angle.

Step-by-step explanation:

Angle 2 is 86 degrees. Whenever a line is bisected by another line, 4 angles are formed. The opposite angles aka the kissing V's have the same angle measurement. Angle 2 and 86-degrees are the kissing V's here, thus they have the same angle measure.

7 0

2 years ago