1. a+3a+4b=5b
2. a+3a=5b-4b
3. 4a=5b-4b
4. 4a=b
a=1/4b
(I think 1/4b is the answer) hope this helps :)
Answer:
32
Step-by-step explanation:
The three consecutive numbers are: 32, 33, 34
They add up to 99
Answer:
see explanation
Step-by-step explanation:
The common difference d of an arithmetic sequence is
d =
-
=
- 
Substitute in values and solve for k, that is
5k - 1 - 2k = 6k + 2 - (5k - 1)
3k - 1 = 6k + 2 - 5k + 1
3k - 1 = k + 3 ( subtract k from both sides )
2k - 1 = 3 ( add 1 to both sides )
2k = 4 ⇒ k = 2
--------------------------------------------------------
The n th term of an arithmetic sequence is
=
+ (n - 1)d
= 2k = 2 × 2 = 4 and
d = 5k - 1 - 2k = 3k - 1 = (3 × 2) - 1 = 5
Hence
= 4 + (7 × 5) = 4 + 35 = 39
Answer:
I'm assuming you mean a compression of factor 6
In that case, it will be h = 1/6x