Option A
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Answer:
C
Step-by-step explanation:
A
(m² - 3m + 2) / (m² - m)
we see due to a little bit of experience with expressions and multiplications of expressions that
(m² - 3m + 2) = (m - 2)(m - 1)
(m² - m) = m(m - 1)
so,
(m - 2)(m - 1) / (m(m - 1)) = (m - 2) / m
so, that's not it.
B
(m² - 2m + 1) / (m - 1)
we see again
(m² - 2m + 1) = (m - 1)(m - 1)
so,
(m - 1)(m - 1) / (m - 1) = m - 1
so, that's not it.
C
(m² - m - 2) / (m² - 1)
we see again
(m² - m - 2) = (m - 2)(m + 1)
and
(m² - 1) = (m + 1)(m - 1)
so,
(m - 2)(m + 1) / ((m + 1)(m - 1)) = (m - 2) / (m - 1)
yes, that is the solution.
D
(2m² - 4m) / (2(m - 2))
2m(m - 2) / (2(m - 2)) = 2m/2 = m
no, that is not a solution.
Answer:
I) |xz| ≈ 28.6 km
II) |yz| ≈ 34.8 km
Step-by-step explanation:
Let's assume that the position of ship due south of x is z (aà pictor representation of the question is attached)
|xy| = 20 km, |xz| = ?, |yz| = ?, θ(y) = 55°
Using Trigonometric ratio - SOHCAHTOA
I) Tan θ = |xz| ÷ |xy| ⇒ Tan 55° = |xz| ÷ 20
|xz| = 20 * Tan 55 = 20 * 1.428
|xz| = 28.56 km
|xz| ≈ <u>28.6 km</u>
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II) Cos θ = |xy| ÷ |yz| ⇒ Cos 55° = 20 ÷ |yz|
|yz| * Cos 55° = 20 ⇒ |yz| = 20 ÷ Cos 55°
|yz| = 20 ÷ 0.574 = 34.84 km
|yz| ≈ <u>34.8 km</u>
Answer:
6x^2+5x-6
Step-by-step explanation:
