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2 years ago

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To find the height of a pole, a surveyor moves 120 feet away from the base of the pole and then, with a transit 8 feet tall, mea

sures the angle of elevation to the top of the pole to be 26. to the nearest foot, what is the height of the pole

1 answer:

Vikki [24]2 years ago

6 0

Refer to the figure.
Let AB be the height of the pole; CD be the height of the transit; BC is the distance from the base of the pole to the transit.

Triangle ADE is a right triangle with angle D measuring 26 degrees. Using the tangent function, we have
$tan\:26^{\circ} =\frac{AE}{120}$
So,
$AE=120\:tan\:26^{\circ}$
$AE=58.53\:$

Therefore, the overall height of the pole is
$AB=58.53+8=66.53\:feet$

The height of the pole is 66.53 feet.

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Answer:

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Step-by-step explanation:

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$i=2\quad :\quad \frac{4!}{2!\left(4-2\right)!}3^2x^2$

$i=3\quad :\quad \frac{4!}{3!\left(4-3\right)!}3^1x^3$

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$=81+108x+54x^2+12x^3+x^4$

$=x^4+12x^3+54x^2+108x+81$

Therefore,

$\left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81$

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