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Liono4ka [1.6K]
2 years ago
6

Frank, who lives in texas, and his sister lilly, who lives in japan, correspond regularly. From what he can tell from the postma

rks on both his and his sister’s letters, it appears that it takes longer for lilly’s mail from japan to reach him in texas than it does for his letters from texas to reach her in japan. When frank called his post office to ask if there was a reason for this, the postmaster told him that the delivery time of letters in both directions should be the same. Frank and his sister decided to collect data to see if letters from japan to texas take longer to be delivered than letters from texas to japan. They recorded the delivery time in days. After convincing themselves that the assumptions were reasonable, they performed a two-sample t-test and obtained the following computer output.
SAT
1 answer:
ehidna [41]2 years ago
3 0

Answer:

(A) There is convincing evidence that there is no difference in the mean delivery times.

(B) There is convincing evidence that there is a difference in the mean delivery times.

(C) There is convincing evidence that the mean delivery time from Japan to Texas is greater than the mean delivery time from Texas to Japan.

(D) There is not convincing evidence that the mean delivery time from Japan to Texas is greater than the mean delivery time from Texas to Japan.

(E) The t-test cannot be used for sample sizes that are this small.

Explanation:

The correct option is;

(A) There is convincing evidence that there is no difference in the mean delivery times.

Step-by-step explanation:

Here we have the formula for the two-sample t-test given s;

 

To Texas N₁ = 12,   =8.74 σ₁ = 2.92 SE Mean₁ = 0.84

To Japan N₂ = 9   = 6.75 σ₂ = 2.56 SE Mean₁ = 0.85

t =   1.667

Where the null hypothesis is

mu To Texas = mu To Japan and the alternative is

mu To Texas > mu To Japan

Here since the observed P value of P = 0.058 is greater than the significance level of 0.05 we fail to reject the null hypothesis and we will therefore, not accept the alternative hypothesis.

Hence, there is convincing evidence that there is no difference in the mean delivery times.  

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Answer is 112%

kinda skeptical about my answer but i am going to give it my best shot, sorry if i get it wrong.

In percent-type questions I always go by this formula:

not a %                            %

original number       :     100%

new number            :      new %

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here, the original numbers are 240 and 180 and the new % is +30% and -10% now let plastic be P and metal be M and let's elaborate this a bit further

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240:100+30\\X:130 \\

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240*130 = 100X\\31200 = 100X\\312=X

the second machine took in 312 plastic bottles, let's save this answer for later

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the first recycling machine took in 180 metal cans while the second took in 10% <u>less</u> plastic bottles, we do the same thing and find the new number, this time let it be Y:

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90 is the new % here; also, notice how sometimes you either add or subtract percents, depending on what the problem demands.

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Now we can conclude that the first recycling machine took in 240  plastic bottles and 180 metal cans and the second took in 312 plastic bottles and 162 metal cans.

here comes the hardest bit to apprehend and the final part of this problem, "the second machine recycled what percent (%) more items than the first?"

in other words, how much percent did the second machine recycle more.

to find that percent, first we need to add the plastic and metal "items" of both machines individually and turn them into percents: let the first machine be A and second machine be B:

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again, using the same formula to find the new percent, let that percent be Z; plugging both A and B respectively:

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