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3 years ago

Use a Pythagorean Triple to find x.

SAT

1 answer:

dlinn [17]3 years ago

5 0

Explanation:

Given

perpendicular (p) = 48

base(b) = 14

hypotenuse (h) = x = ?

We know by using Pythagoras theorem

x² = p² + b²

x² = 48² + 14²

x² =2304 + 196

x² = 2500

x = √2500

Therefore x = 50

Hope it will help you :)

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philly and boston were working on a project in carpentry class. they needed to cut 5 lengths of 234 feet from a board. how long

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or 5 lengths of 234 feet to be cut from a board, the board must have a length of at least 1170 feet.

Let x represent the total length of the board so as to allow for the cutting of 5 lengths.

Since each length needed to be cut is 234 feet, hence:

x = number of lengths × feet per board

x = 5 lengths × 234 feet

x = 1170 feet

Hence for 5 lengths of 234 feet to be cut from a board, the board must have a length of at least 1170 feet.

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The professor informs the class that there will be a test next week. what is the probability that a randomly selected student st

marusya05 [52]

The probability that students who were randomly selected studied for the test, if they pass it with a B or higher grade is: D. 0.80.

<h3>How to calculate the probability?</h3>

In this exercise, you're required to determine the probability that students who were randomly selected studied for the test, if they pass it with a B or higher grade. Thus, we would apply Bayes's theorem.

Let S represent studied for.

Let B represent a score of B or higher grade

Therefore, we need to find P(S|B):

$S|B = \frac{B|S \times S}{B|S \times S\; +\; B|S' \times S'} \\\\S|B = \frac{0.55 \times 0.6}{0.55 \times 0.6 \;+ \;0.2 \times 0.4}\\\\S|B =\frac{0.33}{0.33 + 0.08} \\\\S|B =\frac{0.33}{0.41}$

S|B = 0.80.

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<u>Complete Question:</u>

At the beginning of the semester, a professor tells students that if they study for the tests, then there is a 55% chance they will get a B or higher on the tests. If they do not study, there is a 20% chance that they will get a B or higher on the tests. The professor knows from prior surveys that 60% of students study for the tests. The probabilities are displayed in the tree diagram.

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