I dont know man...im tryna answer questions so i can ask mine :(
Answer:
Step-by-step explanation:
x-3 = 0
x = 3
x + 4 = 0
x = -4
x - 2 = 0
x = 2
x = 3, -4, 2
Answer:
Distance LM = 5.20 unit (Approx.)
Step-by-step explanation:
Given coordinates;
L(1, 4, 7) and M(2, 9, 8)
Find:
Distance LM
Computation:
Distance between three-dimensional plane = √(x2 - x1)² + (y2 - y1)² + (z2 - z1)²
Distance LM = √(2 - 1)² + (9 - 4)² + (8 - 7)²
Distance LM = √(1)² + (5)² + (1)²
Distance LM = √1 + 25 + 1
Distance LM = √27
Distance LM = 3√3 unit
Distance LM = 3(1.732)
Distance LM = 5.196
Distance LM = 5.20 unit (Approx.)
Answer:
for the first equation
f(-3) = 34
f(4) = 6
for the 2nd equation
f(-3) = -56
f(4) ÷ 70
Step-by-step explanation:
my work is attached in a picture.
all you do is substitute each x value into each equation
Answer:
3/2
Step-by-step explanation:
MNOP to ABCD: The answer has to be greater than one because ABCD increases in size from MNOP.
To get the scale factor you have to compare the sides.
Line AD = 6 in.
Line MP = 4 in.
6/4 = 3/2
