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2 years ago

8

Keith opened a credit card and spent $55. Which of the following represents the situation?

2 answers:

raketka [301]2 years ago

3 0

Keith don’t have 55 dollars no more

Goryan [66]2 years ago

3 0

Answer:

B

Step-by-step explanation:

I think B because he opened credit card and not yet deposit and then he spent $55.

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2 points) Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One

Stells [14]

$y'=(t+y)^2-1$

Substitute $u=t+y$ , so that $u'=y'$ , and

$u'=u^2-1$

which is separable as

$\dfrac{u'}{u^2-1}=1$

Integrate both sides with respect to $t$ . For the integral on the left, first split into partial fractions:

$\dfrac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)=1$

$\displaystyle\int\frac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)\,\mathrm dt=\int\mathrm dt$

$\dfrac12(\ln|u-1|-\ln|u+1|)=t+C$

Solve for $u$ :

$\dfrac12\ln\left|\dfrac{u-1}{u+1}\right|=t+C$

$\ln\left|1-\dfrac2{u+1}\right|=2t+C$

$1-\dfrac2{u+1}=e^{2t+C}=Ce^{2t}$

$\dfrac2{u+1}=1-Ce^{2t}$

$\dfrac{u+1}2=\dfrac1{1-Ce^{2t}}$

$u=\dfrac2{1-Ce^{2t}}-1$

Replace $u$ and solve for $y$ :

$t+y=\dfrac2{1-Ce^{2t}}-1$

$y=\dfrac2{1-Ce^{2t}}-1-t$

Now use the given initial condition to solve for $C$ :

$y(3)=4\implies4=\dfrac2{1-Ce^6}-1-3\implies C=\dfrac3{4e^6}$

so that the particular solution is

$y=\dfrac2{1-\frac34e^{2t-6}}-1-t=\boxed{\dfrac8{4-3e^{2t-6}}-1-t}$

3 0

3 years ago

I need help with #11 - #14.

Aleonysh [2.5K]

Answer:

I can get you jump started a bit.

Step-by-step explanation:

So Each of those pairs of figures are Similar.

This means they have equal angle measures but different side lengths.

To find it, we have to make a <u>Proportion:</u>

<u>Example: #11</u>

<u /> $\frac{x+1}{3x+1} =\frac{8}{20}$ <u />

So let's solve the first one!

$24x+8=20x+20\\4x=12\\x=3$

Easy As Pie!

If you need more help, contact me! :)

Hope this Helps!

P.S. Stay Safe!

6 0

3 years ago

Read 2 more answers

What is the value of (7 – 3i)(6 + i)?

Dimas [21]

45 - 11i is the answer! And make sure you double check.

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3 years ago

If 112 sections are 34 mile long, how long is each section?

Ber [7]

Answer:

About 3.29 miles long for each section

Step-by-step explanation:

Find unit rate so 112/34 and you’d get 3.29 rounded.

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3 years ago

Which regression equation best fits these data?

Vsevolod [243]

Answer:

the answer is D

Step-by-step explanation:

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