Using the Central Limit Theorem, it is found that the shape of the sampling distribution of the sample mean wingspan is normal.
<h3>What is the Central Limit Theorem?</h3>
It states that the sampling distribution of sample means of size n, from a normally distributed population with mean 
and standard deviation 
, is normally distributed with mean and standard error 
.
Hence, applying the <em>Central Limit Theorem</em> in this problem, the shape of the sampling distribution of the sample mean wingspan is normal.
More can be learned about the Central Limit Theorem at brainly.com/question/24663213
First step: Convert 24kg to Newtons by multiplying by gravity, or 9.8.
You get 235.2 N
Next: F = m*a
If you draw a free body diagram, you will notice that the Net Force is equal to the Applied Force minus the Frictional Force.
Frictional Force is Ff = μ * Fn
Ff = .23 * 235.2
585 - 54.096 = 24*a
530.904 = 24*a
a = 22.121 m/s
Let me know if any of this doesn't make sense.
Answer:
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Answer:
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