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2 years ago

50 POINTS WILL MAKE BRAINLIEST!!!!

Chemistry

1 answer:

Bad White [126]2 years ago

5 0

Answer: An example:

Measure the distance between the center of the spreading center (red) and the border between dark yellow and light green (65 Ma point) I measured 2 cm Since the scale on the map is 1 cm = 475 km, calculate the real distance that the plate has moved over the past 65 Ma 2 cm * 475 km/cm = 950 km = 95,000,000 cm = 9.5 * 107 cm Determine the length of time that the plate has been moving65 million years = 65,000,000 years = 6.5 * 107 yearsUse the above equation to calculate spreading rateR = d/t or R = 9.5 * 107 cm / 6.5 * 107 years = 1.46 cm/yr

Explanation:

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Electrons is an excited state are more likely to enter into chemical reactions.

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3 years ago

An isotope of an element, atomic number Z, has a mass number 2z+4. How many neutrons are there in the nucleus of the element?

Svet_ta [14]

Answer:

z+4

Explanation:

An isotope of an element, atomic number Z, has a mass number 2z+4. How many neutrons are there in the nucleus of the element?o

protons + neutrons =mass number

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2 years ago

What causes cold, deep ocean currents to form in the ocean currents near the poles?

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2 years ago

Practice Problem Website: https://www3.nd.edu/~smithgrp/structure/workbook.html

yarga [219]

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3 years ago

A 7.300 gram sample of aluminum was quantitatively combined with a sample of selenium to form a compound. The compound weighed 3

adelina 88 [10]

Answer:

The empirical formula is Al2Se3

Explanation:

Step 1: Data given

Mass of the sample of aluminium = 7.300 grams

Mass of the compound = 39.35 grams

Molar mass of aluminium = 26.98 g/mol

Molar mass of selenium = 78.96 g/mol

Step 2: Calculate mass of selenium

Mass of selenium = mass of compound - mass of aluminium

Mass of selenium = 39.35 - 7.3 = 32.05 grams

Step 3: Calculate moles of Al

Moles Al = Mass Al/ Molar mass Al

Moles Al = 7.300 grams / 26.98 g/mol

Moles Al = 0.2706 moles

Step 4: Calculate moles of Se

Moles Se = Mass Se / Molar mass Se

Moles Se =32.05 g / 78.96 g/mol

Moles Se = 0.4059 moles

Step 5: Divide through the smallest amount of mol

Aluminium: 0.2706 / 0.2706 = 1

Selenium: 0.4059/0.2706 = 1.5

This means for each mol aluminium, we have 1.5 moles of selenium

For each 2 moles of aluminium, we have 3 moles of selenium

The empirical formula is Al2Se3

This is aluminium(III) selenide.

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3 years ago