a) 70.1 m
The ball is moving by uniformly accelerated motion, with constant acceleration 
(acceleration due to gravity) towards the ground. The height of the ball at time t is given by the equation
where 
is the height of the ball at time t=0. Substituting t=1 s, we can find the height of the ball 1 seconds after it has been dropped:
b) 3.9 s
We can still use the same equation we used in the previous part of the problem:
This time, we want to find the time t at which the ball hits the ground, which means the time t at which h(t)=0. So we have
And solving for t we find
You would use the Pythagorean Theorem.
a2 + b2 = c2
302 + x2 = 752
900 + x2 = 5625
900 – 900 + x2 = 5625
X2 = 5625
√(x^2 ) = √5625
X = 75
It is 75 yards wide. I've included a drawing of the rectangle if it helps.
Answer:
Exact Form:
f=8/15
Decimal Form:
f=1.875
Step-by-step explanation:
45×2f = 4×12
90f = 48
48/90 = 24/45 = 8/15
Answer:
y = -1/2 (4 x + 2)
Step-by-step explanation:
A system of two equations with no solution will consist of equations for <em>parallel lines</em>. The line will be parallel if they have the same slope (x-coefficient) and different y-intercepts.
The given line has a slope of -2, so eliminating the last two choices.
The first two choices can be expanded to slope-intercept form:
y = negative 2 (x minus one-half) ⇒ y = -2x +1 . . . same as given line
y = negative one-half (4 x + 2) ⇒ y = -2x -1 . . . parallel line
There will be no solution if another equation is ...
y = -1/2(4x +2)
Answer:
my pp is bigger than the holocaust
Step-by-step explanation:
