Answer:
The 98% confidence interval for the mean purchases of all customers is ($37.40, $61.74).
Step-by-step explanation:
We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of .
So it is z with a pvalue of , so
Now, find M as such
In which is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the mean subtracted by M. So it is 49.57 - 12.17 = $37.40.
The upper end of the interval is the mean added to M. So it is 49.57 + 12.17 = $61.74.
The 98% confidence interval for the mean purchases of all customers is ($37.40, $61.74).
Answer:
area = 99.33units²
Step-by-step explanation:
b + 1/2p + l
<em>good luck, i hope this helps :)</em>
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Hello!
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❖ The median of the data is 23.
You keep crossing out numbers until you get to the middle point. First, you cross of the beginning and the end which is 21 and 25. You then cross out 22 and 24. The remaining number is 23. When you are working with an even amount of numbers, you are left with 2 numbers so you add those 2 numbers and divide by 2.
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So to figure out 10% of this would be to remove the 0. that would be six. since 30÷10 is 3, we have to do 6×3. that would be 18, so 30% of 60 is 18