Question

If you're good at exact values of trigonometry please help meeeee

Answer 1

Answer:

x = 6 + 16 sqrt(3) / 3  or equivalently 6 + 16/sqrt(3)

Step-by-step explanation:

Have enough data to solve only for x in the diagram.

The lengths that make up the base are respectively from left to right

x1 = 4 cot(60) = 4 (3/sqrt(3)) = 4sqrt(3)  m

x2 = 6 m

x3 = 4 cot(30) = 4 ( sqrt(3) / 3 ) = 4/ sqrt(3) = (4/3)sqrt(3) m

Altogether

Base, x = 4sqrt(3)/3 + 6 + 2 sqrt(3)

= 6 + 16 sqrt(3) / 3  or equivalently 6 + 16/sqrt(3)

Answer 2

Answer:

Step-by-step explanation:

First triangle: angles are in the ratio = 30 : 60 : 90

So, the ratio of sides = a : a√3 : 2a

a√3 = 4 m

a  * 1.732 = 4

a = 4/1.732

a = 2.31

Now, in the second triangle, angles are in the ratio = 30 : 60 : 90

So, the ratio of sides = b : b√3 : 2b

b = 4 m

b√3 = 4 * 1.732 = 6.928 m

x = a + 6 + b

x = 2.31 + 6 + 6.928

x = 15.23 m