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Sunny_sXe [5.5K]
3 years ago
11

Question 3 of 10

Mathematics
1 answer:
fenix001 [56]3 years ago
4 0

Answer:

B. 20

Step-by-step explanation:

Because it is twice as much as expected.

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Coefficient and variable in 9a+11p
Paha777 [63]
There are two coefficients and two variables.
The coefficients are 9 and 11.
The variables are a and p.
Hope that helped!
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3 years ago
Solve for m: (5m-3n)/q=f
LenaWriter [7]
Do you need the work, or just the answer?
7 0
4 years ago
Find the distance between the two points in simplest radical form.
SCORPION-xisa [38]

Answer:

The answer is \sqrt{61}

.

Step-by-step explanation:

The distance formula:

d =  \sqrt{(x_2 - x_1)^{2} + (y_2 - y_1)^{2}  }

.

☆All we need to do is plug in!

d =  \sqrt{(x_2 - x_1)^{2} + (y_2 - y_1)^{2}  }  \\ \\  d =   \sqrt{( - 1 - 4) ^{2} + ( - 9 - ( - 3))^{2}  }  \\ d =  \sqrt{( - 5)^{2} + ( - 6) ^{2}}  \\ d  =  \sqrt{25 + 36 }  \\  d =  \sqrt{61}

5 0
3 years ago
Use complete sentences to explain how you could use a number line to explain why 2 < 3 < 5. Please. :D
Svetach [21]
Two is less than three which is also less than 5.


When put into a number line from 0 to 10, it shows that 2 is closest to 0 while 5 is closest to 10 and three, will be in between 2 and 5. This shows that as you go from 2 to 3, the number increased and, it continues to increase when you go from 3 to 5. This shows that 2 is less than 3 and 3 is less than 5.
7 0
4 years ago
Find cos θ given that cos 2θ = 5/6 and 0 ≤ θ < π/2. Give an exact answer
trasher [3.6K]
\bf \textit{Double Angle Identities}
\\ \quad \\
sin(2\theta)=2sin(\theta)cos(\theta)
\\ \quad \\
cos(2\theta)=
\begin{cases}
cos^2(\theta)-sin^2(\theta)\\
1-2sin^2(\theta)\\
\boxed{2cos^2(\theta)-1}
\end{cases}
\\ \quad \\
tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\\\\
-------------------------------\\\\


\bf cos(2\theta)=\cfrac{5}{6}\implies 2cos^2(\theta)-1=\cfrac{5}{6}\implies 2cos^2(\theta)=\cfrac{5}{6}+1
\\\\\\
2cos^2(\theta)=\cfrac{11}{6}\implies cos^2(\theta)=\cfrac{11}{12}\implies cos(\theta)=\pm\sqrt{\cfrac{11}{12}}


now, bear in mind, the square root gives us +/- versions, so, which is it? well, we know the angle is in the range of "<span>0 ≤ θ < π/2", that simply means the 1st quadrant, so, we'll use the positive one then

</span>\bf cos(\theta)=\cfrac{\sqrt{11}}{\sqrt{12}}\implies cos(\theta)=\cfrac{\sqrt{11}}{2\sqrt{3}}&#10;\\\\\\&#10;\textit{now, let's rationalize the denominator}&#10;\\\\\\&#10;\cfrac{\sqrt{11}}{2\sqrt{3}}\cdot \cfrac{\sqrt{3}}{\sqrt{3}}\implies \cfrac{\sqrt{11}\cdot \sqrt{3}}{2\sqrt{3^2}}\implies \cfrac{\sqrt{11\cdot 33}}{2\cdot 3}\implies \boxed{\cfrac{\sqrt{33}}{6}}<span>
</span>
3 0
4 years ago
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