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2 years ago

10

Let g(x) = 2x and h(x) = x2 + 4. Evaluate (h ∘ g)(−5).

1 answer:

Zolol [24]2 years ago

6 0

Hi! the answer should be 104

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Formula: h(g(x))

1) First you want to take the -5 and plug that into the given equation for g(x)

• 2(-5)= -10

2) Next you want to take the -10 and plug it into the equation for h(x)

• (-10)²+4= 104

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Need to find volume, step by step explanation pls <br><br><br><br>

worty [1.4K]

Given:

A figure of combination of hemisphere, cylinder and cone.

Radius of hemisphere, cylinder and cone = 6 units.

Height of cylinder = 12 units

Slant height of cone = 10 units.

To find:

The volume of the given figure.

Solution:

Volume of hemisphere is:

$V_1=\dfrac{2}{3}\pi r^3$

Where, r is the radius of the hemisphere.

$V_1=\dfrac{2}{3}(3.14)(6)^3$

$V_1=\dfrac{6.28}{3}(216)$

$V_1=452.16$

Volume of cylinder is:

$V_2=\pi r^2h$

Where, r is the radius of the cylinder and h is the height of the cylinder.

$V_2=(3.14)(6)^2(12)$

$V_2=(3.14)(36)(12)$

$V_2=1356.48$

We know that,

$l^2=r^2+h^2$ [Pythagoras theorem]

Where, l is length, r is the radius and h is the height of the cone.

$(10)^2=(6)^2+h^2$

$100-36=h^2$

$\sqrt{64}=h$

$8=h$

Volume of cone is:

$V_3=\dfrac{1}{3}\pi r^2h$

Where, r is the radius of the cone and h is the height of the cone.

$V_3=\dfrac{1}{3}(3.14)(6)^2(8)$

$V_3=\dfrac{25.12}{3}(36)$

$V_3=301.44$

Now, the volume of the combined figure is:

$V=V_1+V_2+V_3$

$V=452.16+1356.48+301.44$

$V=2110.08$

Therefore, the volume of the given figure is 2110.08 cubic units.

7 0

2 years ago

A function is given: f (x) = 2x + 3<br> What is the value of f(-2)?

Nadusha1986 [10]

Answer:

f(-2) = -1

Step-by-step explanation:

-2 is x, so replace x as -2 into the equation

f (-2) = 2(-2) + 3

f (-2) = -4 + 3

f (-2) = -1

5 0

3 years ago

Select the relations that are functions.

Arlecino [84]

Answer:

Depending on how the input of each function defined,

The first choice $\left\lbrace(a, 1),\, (6, 1), \, (C, 1)\right\rbrace$ ,
The third choice $\left\lbrace(1, a),\, (2, a), \, (3, a)\right\rbrace$
The fourth choice $\left\lbrace(a, a),\, (b, b), \, (c, c)\right\rbrace$

might be functions.

Step-by-step explanation:

A function between two sets (domain and range) should

be defined for all elements in the domain, and
map each element from the domain to exactly one element in the range.

The second choice can't be a function since the element $a$ from the domain is mapped to more than one element in the range.

Keep in mind that a function should be defined for all elements in its domain. For the first relation to be a function, its domain needs to be $\lbrace a,\, 6, \, C\rbrace$ . Similarly, the domain for the third and fourth relations should be $\lbrace 1,\, 2, \, 3\rbrace$ and $\lbrace a,\, b, \, c\rbrace$

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3 years ago

What is 5-2+(9÷1)×9+0

Anna [14]

The answer is 84 because of process priority

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3 years ago

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I need help I’m timed<br> what is the y- intercept of the linear function? <br> y= 1/2 x + 4

Gennadij [26K]

Answer: (0,4)

Step-by-step explanation:

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3 years ago