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Katena32 [7]
2 years ago
5

If t and s are inversely proportional and t = 4 when s = 40, then what is t when s = 80?

Mathematics
2 answers:
Paraphin [41]2 years ago
5 0

Answer:

8

Step-by-step explanation:

AlekseyPX2 years ago
4 0

Answer:

1 is answer.

Step-by-step explanation:

it will help

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Please help me with the question please ASAP ASAP please ASAP
Rudiy27

Answer:

V = 672; SA = 544; LA = 448

Step-by-step explanation:

3 0
2 years ago
Dennis arrived at Sullivan's at 10:15am the store opens at 11:00 how long will he have to wait
steposvetlana [31]
He will have to wait 45 minutes
6 0
3 years ago
Read 2 more answers
Solve the following triangle in which given sides are<br> a=7 b=7 c=9
blagie [28]
We have an isosceles triangle;
A=opposite angle side a.
B=opposite angle side b.
C=opposite angle side c.

A=B
Method 1:

We can divide the isosceles triangle in two right triangles,
hypotenuse=7
side=9/2=4.5

B=A=arccossine (4.5/7)=49.994799...º≈50º
C/2=90º-50º=40º  ⇒ C=2*40º=80º

Answer:
a=7;  A=50º
b=7;  B=50º
<span>c=9;  C=80º

Method 2:
Law of cosines:
a²=b²+c²-2bcCosA  ⇒CosA=(a²-b²-c²)/(-2bc)
CosA=(49-49-81) / (-126)=0.642857
A=arco cos (81/126)≈50º

B=A=50º

A+B+C=180º
50º+50º+C=180º
C=180º-100º
C=80º

Answer:

</span>a=7;  A=50º
b=7;  B=50º
<span>c=9;  C=80º</span>

8 0
3 years ago
An insurance company has 25,000 automobile policy holders. If the yearly claim of a policy holder is a random variable with mean
telo118 [61]

Answer:

P(T>8300000)=1-P(T

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Data given

n = 25000 represent the automobile policy holders

\mu= 320 represent the population mean

\sigma =540 represent the population standard deviation

Let T the variable that represent the total of interest on this case. We can assume that the random variable for an individual policy holder is given by:

X\sim N(\mu = 540, \sigma=540)

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Solution to the problem

First we need to find the distribution for the random variable T like this:

\bar X = \frac{\sum_{i=1}^n x_i}{n}

And the total T is given by:

T=\sum_{i=1}^n X_i =n \bar X

We can find the expected value, variance and deviation for this random variable like this:

E(T)= n E(\bar X) = n \mu = 25000*320=8000000

Var(T)= Var(n\bar X)= n^2 Var(\bar X) = n^2 \frac{\sigma^2}{n}=n \sigma^2 =25000*(540^2)=7290000000

Sd(T)=\sqrt{7290000000}=85381.497

And we are interested on this probability:

P(T>8300000)

And we can use the Z score formula given by:

Z=\frac{T-E(T)}{\sigma_T}

P(T>8300000)=1-P(T

6 0
3 years ago
In the figure, b and c are parallel lines. Which of the following statements are true?
Helen [10]

Answer:

1. No, Joe is not correct

2. \angle 5=72^{\circ}

Step-by-step explanation:

Given: b and c are parallel lines

To find:

1. whether the given statement is correct or not

2. \angle 5

Solution:

1.

Sum of two angles that form a linear pair is equal to 180^{\circ}

\angle 3+72^{\circ}=180^{\circ} (linear pair)

\angle 3=180^{\circ}-72^{\circ}=108^{\circ}\neq 90^{\circ}

So, Joe is not correct

2.

If two lines are parallel then alternate interior angles are equal.

As b and c are parallel lines,

\angle 5=72^{\circ} (alternate interior angles)

4 0
3 years ago
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