I think you would subtract 16 from 29 to get the answer try it and see what happens
Area = Length x width so you would divide 25 by ten to get 2.5 then you double check by multiplying 2.5x 10 an you get 25 so its 2.5.
We know that
Part a) <span>Find the fifth term of the arithmetic sequence in which t1 = 3 and tn = tn-1 + 4
t1=3
t2=t1+4----> 3+4-----> 7
t3=t2+4-----> 7+4----> 11
t4=t3+4-----> 11+4---> 15
t5=t4+4-----> 15+4---> 19
the answer Part a) is 19
Part b) </span><span>Find the tenth term of the arithmetic sequence in which t1 = 2 and t4 = -10
we know that
tn=t1+(n-1)*d-----> d=[tn-t1]/(n-1)
t1=2
t4=-10
n=4
find the value of d
d=[-10-2]/(4-1)-----> d=-12/3----> d=-4
find the </span>tenth term (t10)
t10=t1+(10-1)*(-4)----> t10=2+9*(-4)----> t10=-34
the answer Part b) is -34
Part c) <span>Find the fifth term of the geometric sequence in which t1 = 3 and tn = 2tn-1
t1=3
t2=2*t1----> 2*3----> 6
t3=2*t2----> 2*6----> 12
t4=2*t3-----> 2*12---> 24
t2=2*t4----> 2*24----> 48
the answer Part c) is 48</span>
Answer:
is this actually a question?
Step-by-step explanation:
According to the question statement, the total sum of students is 221, which includes the students that ride on bus and the students that ride in a van.
The students that ride in a van are five, the students that ride on bus are 6 times s which is the product of the number of buses and the number of students that are on each bus.
Write all this information into an equation, this way:
Now, solve the equation for s to find the number of students that are on each bus.
There are 36 students on each bus.
