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ehidna [41]
3 years ago
11

Find the fifth term of the arithmetic sequence in which t1 = 3 and tn = tn-1 + 4. A) 5 B) 7 C) 19 D) 23 2) Find the tenth term o

f the arithmetic sequence in which t1 = 2 and t4 = -10. A) -10 B) -34 C) -38 D) -106 3) Find the fifth term of the geometric sequence in which t1 = 3 and tn = 2tn-1. A) 5 B) 6 C) 48 D) 96
Mathematics
1 answer:
Sergeu [11.5K]3 years ago
3 0
We know that

Part a) <span>Find the fifth term of the arithmetic sequence in which t1 = 3 and tn = tn-1 + 4
t1=3
t2=t1+4----> 3+4-----> 7
t3=t2+4-----> 7+4----> 11
t4=t3+4-----> 11+4---> 15
t5=t4+4-----> 15+4---> 19

the answer Part a) is 19

Part b) </span><span>Find the tenth term of the arithmetic sequence in which t1 = 2 and t4 = -10

we know that 
tn=t1+(n-1)*d-----> d=[tn-t1]/(n-1)
t1=2
t4=-10
n=4
find the value of d
d=[-10-2]/(4-1)-----> d=-12/3----> d=-4
find the </span>tenth term (t10)
t10=t1+(10-1)*(-4)----> t10=2+9*(-4)----> t10=-34

the answer Part b) is -34

Part c) <span>Find the fifth term of the geometric sequence in which t1 = 3 and tn = 2tn-1
t1=3
t2=2*t1----> 2*3----> 6
t3=2*t2----> 2*6----> 12
t4=2*t3-----> 2*12---> 24
t2=2*t4----> 2*24----> 48

the answer Part c) is 48</span>
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We're given the Arithmetic Progression <em>-24, -4, 16, 36 ...</em> .

We know that a term in an AP is generally represented as:

\bf a_n\ =\ a\ +\ (n\ -\ 1)d

where,

  • a = the first term in the sequence
  • n = the number of the term/number of terms
  • d = difference between two terms

We need to find \sf a_2_3.

From the given progression, we have:

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  • n = 23
  • d = (-24 - (-4) = -20

Using these in the formula,

\sf a_2_3\ =\ a\ +\ (n\ -\ 1)d\\\\\\a_2_3\ =\ -24\ +\ (23\ -\ 1)\ \times\ (-20)\\\\\\a_2_3\ =\ -24\ +\ 22\ \times (-20)\\\\\\a_2_3\ =\ -24\ -\ 440\\\\\\\bf a_2_3\ =\ -464

Therefore, the 23rd term in the AP is -464.

Hope it helps. :)

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Maya is 14 years old. Her brother Jorge is 3 years more than half her age. Which of the following is the correct expression for
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KengaRu [80]

A rectangle with dimensions x and y has perimeter 20 if

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So, the dimensions of the rectangle must be x and 10-x, where x ranges from 0 to 10 (both extremes are excluded, otherwise you'd have a degenerate rectangle, which is actually a segment).

So, all the possible areas are given by the product of the dimensions, i.e.

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The function f(x)=-x^2+10x represents a parabola, facing downwards, and thus it admits a maximum, which is its vertex.

In particular, the vertex of this parabola is given by

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This is a well known theorem: if you fix the perimeter, the rectangle with the largest area is the square yielding that perimeter.

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