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Murrr4er [49]
2 years ago
9

there arre 221 students on a fiel trip five students ride in a van the rest of the students fill the 6 buses enter an equation t

hat can be solved to find the numbers of students, S, that are on each bus. Enter the numbers of students that are on each bus.
Mathematics
1 answer:
iren2701 [21]2 years ago
3 0

According to the question statement, the total sum of students is 221, which includes the students that ride on bus and the students that ride in a van.

The students that ride in a van are five, the students that ride on bus are 6 times s which is the product of the number of buses and the number of students that are on each bus.

Write all this information into an equation, this way:

6s+5=221

Now, solve the equation for s to find the number of students that are on each bus.

\begin{gathered} 6s+5=221 \\ 6s=216 \\ s=\frac{216}{6} \\ s=36 \end{gathered}

There are 36 students on each bus.

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Jacqueline leaves city a at 2:00 p.m. and drives at a constant speed, traveling west on i-90. she passes city b, 40 mi from city
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4 years ago
5. The distance between two given points (5,2) and (x,5) is 5 units. Find the possible values of x. *​
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<h3>Answers:  x = 1 and x = 9</h3>

============================================================

Explanation:

We'll use the distance formula here. Rather than compute the distance d based on two points given, we'll go in reverse to use the given distance d to find what the coordinate must be to satisfy the conditions.

We're given that d = 5

The first point is (x_1,y_1) = (5,2) and the second point has coordinates of (x_2,y_2) = (x,5) where x is some real number.

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d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\\\5 = \sqrt{(5-x)^2+(2-5)^2}\\\\5 = \sqrt{(5-x)^2+(-3)^2}\\\\5 = \sqrt{(5-x)^2+9}\\\\\sqrt{(5-x)^2+9} = 5\\\\(5-x)^2+9 = 5^2\\\\(5-x)^2+9 = 25\\\\(5-x)^2 = 25-9\\\\(5-x)^2 = 16\\\\5-x = \pm\sqrt{16}\\\\5-x = 4 \ \text{ or } \ 5-x = -4\\\\-x = 4-5 \ \text{ or } \ -x = -4-5\\\\-x = -1 \ \text{ or } \ -x = -9\\\\x = 1 \ \text{ or } \ x = 9\\\\

This means that if we had these three points

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Then segments AB and AC are each 5 units long.

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However, you could factor out the common factors:  2xy(3x+y).
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