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laiz [17]
2 years ago
10

Work out (3.6 x 10^-5) divided by (1.8 x 10^2) give your answer in standard form

Mathematics
1 answer:
Andre45 [30]2 years ago
3 0

Answer:

lol it's 0.002

Step-by-step explanation:

(3.6x10^-5) = 0.000036 divided by (1.8x10^2) is 0.002

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Jason is building a 1 : 180 scale model of a real castle. his model has a rectangular base that is 3 feet wide and 4 feet long.w
balu736 [363]
The area of the actual castle would be 388,800 sq. ft.

We would multiply each of the sides of the scale model both by 180 to find the side lengths of the actual castle.

So...
180 x 4 = 720
180 x 3 = 540

If Area is equal to Length Times Width, all thats left to do is to multiply the two sides together.

720 x 540 = 388,800

Hope this helped! :D
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What is the range of the given function?
Travka [436]

Answer:

-2

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range is y values

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What is 800 divided by 1000
Monica [59]

Answer:


Erm idk what you meant but the answers either 0.8 or .125

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3 years ago
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If 1200 cm2 of material is available to make a box with a square base and an open top, find the largest possible volume of the b
Colt1911 [192]

Answer:

The largest possible volume V is ;

V = l^2 × h

V = 20^2 × 10 = 4000cm^3

Step-by-step explanation:

Given

Volume of a box = length × breadth × height= l×b×h

In this case the box have a square base. i.e l=b

Volume V = l^2 × h

The surface area of a square box

S = 2(lb+lh+bh)

S = 2(l^2 + lh + lh) since l=b

S = 2(l^2 + 2lh)

Given that the box is open top.

S = l^2 + 4lh

And Surface Area of the box is 1200cm^2

1200 = l^2 + 4lh ....1

Making h the subject of formula

h = (1200 - l^2)/4l .....2

Volume is given as

V = l^2 × h

V = l^2 ×(1200 - l^2)/4l

V = (1200l - l^3)/4

the maximum point is at dV/dl = 0

dV/dl = (1200 - 3l^2)/4

dV/dl = (1200 - 3l^2)/4 = 0

3l^2= 1200

l^2 = 1200/3 = 400

l = √400

I = 20cm

Since,

h = (1200 - l^2)/4l

h = (1200 - 20^2)/4×20

h = (800)/80

h = 10cm

The largest possible volume V is ;

V = l^2 × h

V = 20^2 × 10 = 4000cm^3

4 0
3 years ago
Need help with finding foci of parabola
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Hello,
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