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Kryger [21]
4 years ago
15

Dropping a temporary magnet on the floor may destroy its magnetism because _____. the floor absorbs the magnetic field the domai

ns are knocked out of alignment the electrons start spinning the other way the heat generated by the collision destroys the magnetism
Physics
1 answer:
Svetradugi [14.3K]4 years ago
7 0

Answer: Dropping a temporary magnet on the floor may destroy its magnetism because <u>the domains are knocked out of alignment</u>

Explanation:

An object behaves as a magnet when all the domains are aligned in a single direction. A temporary magnet is created when domains are temporarily aligned in the presence of another magnetic field. When this magnet is dropped on the floor, the domains dis-align causing the demagnetization of the magnet.  

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A solid sphere of brass (bulk modulus of 14.0 ✕ 1010 N/m2) with a diameter of 2.20 m is thrown into the ocean. By how much does
astra-53 [7]

Answer:

Diameter decreases by the diameter of 0.0312 m.

Explanation:

Given that,

Bulk modulus =  14.0 × 10¹⁰ N/m²

Diameter d = 2.20 m

Depth = 2.40 km

Pressure = ρ g h = 1030 × 9.81 × 2.4 × 1000

               = 24.25 × 10⁶  N/m²

Volume = \dfrac{4}{3} \pi r^3

         \dfrac{\Delta V}{V}=\dfrac{(\Delta r)^3}{r^3}

Bulk modulus is equal to

B = -\dfrac{\Delta P}{\dfrac{\Delta V}{V} }

now

B = -\dfrac{24.25 \times 10^6}{\dfrac{(\Delta r)^3}{r^3} }

B = -\dfrac{24.25 \times 10^6}{\dfrac{(\Delta r)^3}{1.1^3} }

(\Delta r)^3 = \dfrac{24.25 \times 10^6 \times 1.1^3}{14.0 \times 10^{10}}

Δ r = -0.0156 m

change in diameter

Δ d = -2 × 0.0156

Δ d = -0.0312 m

Diameter decreases by the diameter of 0.0312 m.

7 0
3 years ago
Cassy shoots a large marble (Marble A, mass: 0.06kg) at a smaller marble (Marble B, mass: 0.03kg) that is sitting still. Marble
4vir4ik [10]

The question can be solved using conservation of linear momentum.

M_{a} = 0.06kg and M_{b} = 0.03kg

Let the initial velocity of Marble A be , V_{a1} = 0.7m/s

Let the initial velocity of Marble B be, V_{b1} = 0m/s

Let the velocity of Marble A after collisiong , V_{a2}= -0,02m/s

Let the velocity of Marble B after collision be V_{b2}

From the conservation of linear momentum equation. We get,

M_{a}V_{a1}+M_{b}V_{b1}=M_{a}V_{a2}+M_{b}V_{b2}

Substituting the values we get,

(0.06)(0.7) + 0 = (0.06)(-0.02) + (0.03)V_{b2}

we get, V_{b2} = 1.44m/s

6 0
3 years ago
How fast does a cats hair grow back?
Lady_Fox [76]
It depends on the type of cat....
6 0
4 years ago
Read 2 more answers
A barometer reads 780 mm Hg. Mercury has a density of 1.36 x 10^4 kg /m^3.
iris [78.8K]

The pressure of the atmosphere, when a barometer reads 780 mm Hg.    Mercury which a density of 1.36 x 10^4 kg /m^3 is B 1.1 x 10^5 N/m^2

This problem can be solved using the formula below

P = dgh................. Equation 1

Where P = Pressure of the atmosphere, d = density of the mercury, h = height of the mercury, g = acceleration due to gravity.

From the question,

Given: d = 1.36×10⁴ kg/m³, h = 780 mm = 0.78 m,

Constant: g = 10 m/s²

Substitute these values into equation 1

P = (1.36×10⁴)(10)(0.78)

P = 10.608×10⁴ N/m²

P ≈ 1.1×10⁵ N/m²

Hence the right answer is B. 1.1×10⁵ N/m²

Learn more about Pressure here: brainly.com/question/23603188

7 0
3 years ago
Read 2 more answers
HELP!!!!!!!!!
WARRIOR [948]
I think it would be A
hope this helps.
A and C
5 0
3 years ago
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