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3 years ago

11

What is the answer

2 answers:

babunello [35]3 years ago

7 0

Answer:

It might be B

lara31 [8.8K]3 years ago

4 0

Answer:

<em>c. 11°</em>

Step-by-step explanation:

<em>Hi there ! </em>

<em>(6x - 26) & (11x + 19) supplementary =></em>

<em>6x - 26 + 11x + 19 = 180°</em>

<em>17x - 7 = 180°</em>

<em>17x = 180 + 7</em>

<em>17x = 187</em>

<em>x = 187/17</em>

<em>x = 11°</em>

<em>Good luck ! </em>

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For many years businesses have struggled with the rising cost of health care. But recently, the increases have slowed due to les

kaheart [24]

Answer:

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

The margin of error for this case is given by:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259$

And replacing into the confidence interval formula we got:

$0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941$

$0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459$

And the 95% confidence interval would be given (0.4941;0.5459).

Step-by-step explanation:

Data given and notation

n=1000 represent the random sample taken

$\hat p=0.52$ estimated proportion of of U.S. employers were likely to require higher employee contributions for health care coverage

$\alpha=0.05$ represent the significance level (no given, but is assumed)

Solution to the problem

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

The margin of error for this case is given by:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259$

And replacing into the confidence interval formula we got:

$0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941$

$0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459$

And the 95% confidence interval would be given (0.4941;0.5459).

5 0

3 years ago

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romanna [79]

Answer:

x = 1/3

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS
Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

4x + 1 = 3 - 2x

<u>Step 2: Solve for </u><em><u>x</u></em>

Add 2x on both sides: 6x + 1 = 3
Subtract 1 on both sides: 6x = 2
Divide 6 on both sides: x = 1/3

<u>Step 3: Check</u>

<em>Plug in x to verify it's a solution.</em>

Substitute: 4(1/3) + 1 = 3 - 2(1/3)
Multiply: 4/3 + 1 = 3 - 2/3
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Here we see that 7/3 does indeed equal 7/3.

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Answer:

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Step-by-step explanation:

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Hope this helps! If you have any questions on how I got my answer feel free to ask. Stay safe!

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